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3 years ago

Combine as indicated by the signs. 4/ y^2-9 + 5/y+3

1 answer:

8 0

$\frac{4}{y^{2}-9 } + \frac{5}{y+3} = \frac{4}{(y-3)(y+3) } + \frac{5}{y+3}= \frac{4}{(y-3)(y+3) } + \frac{5(y-3)}{(y-3)(y+3)}=
\\ \\=\frac{4}{(y-3)(y+3) } + \frac{5y-15}{(y-3)(y+3)}= \frac{5y-11}{(y-3)(y+3)}=\frac{5y-11}{y^{2}-9}
$

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Akimi4 [234]

we are given

quadratic equation as

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now, we can find b and c from

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we can see that coefficient of x^2 is 1

so, we will have to make coefficient x^2 as 1

so, we divide both sides by 3

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2 years ago

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Step-by-step explanation:

Frequency is the number of repetitions of a particular observation.

Relative Frequency is the ratio of the frequency of particular observation to the sum of frequencies of all the observations.

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Step-by-step explanation:

Horizontal asymptote y=2

y intercept (0,5)

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