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2 years ago

72 boxes out of 90 sold what percentage sold

Mathematics

1 answer:

ahrayia [7]2 years ago

6 0

Answer:

is what is the math thing at you need help with huh

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40 is 50 percent of which number

FinnZ [79.3K]

Answer:

Step-by-step explanation:

80 divided by 1/2 = 40 therefore 40 is 50% of 80

4 0

3 years ago

Each statement describes a transformation of the graph of y = x2. Which statement correctly describes the graph of y = (x + 4)2

alina1380 [7]

Vertex Form: $y=(x-h)^2+k$ , with (h,k) as the vertex.

So the new equation is in vertex form. And looking at this equation, we see the vertex as (-4,-7) (Remember that y = (x + 4)^2 - 7 can be also written as y = (x - (-4))^2 - 7).

Since negative x-coordinates go to the left on the x-axis and negative y-coordinates go down on the y-axis, your answer is going to be C. It is the graph of y = x^2 translated 7 units down and 4 units to the left.

6 0

3 years ago

Read 2 more answers

Find the output, h, when the input, x, is - 18. h=17+ x/6

Nookie1986 [14]

Answer:

h = 20

Step-by-step explanation:

h = 17 + x/6

h = 17 + (18) / 6

h = 17 + 3

h = 20

5 0

3 years ago

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A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$

3 0

3 years ago

What is the area of the acute triangle given below? A.18 B.72 C.36 D.26

Temka [501]

Hi there!

Area of a triangle: 1/2bh

Substitute 6 for h and 12 for b.

1/2(12)(6)

Multiply (12)(6).

1/2(72)

Divide 72 by 2.

C) 36 sq. units

Hope this helps!

3 0

3 years ago