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Reil [10]
3 years ago
8

Find the Taylor series for f(x) centered at the given value of a. (Assume that f has a power series expansion. Do not show that

Rn(x)→0 . f(x)=lnx, a=
Mathematics
1 answer:
Kobotan [32]3 years ago
3 0

Answer:

Here we just want to find the Taylor series for f(x) = ln(x), centered at the value of a (which we do not know).

Remember that the general Taylor expansion is:

f(x) = f(a) + f'(a)*(x - a) + \frac{1}{2!}*f''(a)(x -a)^2 + ...

for our function we have:

f'(x) =  1/x

f''(x) = -1/x^2

f'''(x) =  (1/2)*(1/x^3)

this is enough, now just let's write the series:

f(x) = ln(a) +  \frac{1}{a} *(x - a) - \frac{1}{2!} *\frac{1}{a^2} *(x - a)^2 + \frac{1}{3!} *\frac{1}{2*a^3} *(x - a)^3 + ....

This is the Taylor series to 3rd degree, you just need to change the value of a for the required value.

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