Could use some help with this math xl problem

Ms. Davenport's class studied the changes in temperature in math class as a part of their study of rational numbers.

Simora [160]

Answer:

D

Step-by-step explanation:

If it was 6 degrees cooler on Monday than it was on Sunday, but also having Tuesday be 4 degrees warmer than Monday, Wednesday would have to be 2 degrees cooler than Tuesday because it is a number that would comply with the limits

7 0

4 years ago

Read 2 more answers

A gym charges a $59 fee plus $7.70 per week that person attends. The total cost y for any number of weeks x can be given using t

lianna [129]

Firstly the equation would be y=7.7x+59
(A)The slope is 7.7 (B) and shows that there is a 7.7 charge per week the person attends.
(A)The y intercept is 59 (B) and is the initial fee that the gym charges.

8 0

3 years ago

Material for a dress costs £5.50 per metre. find the cost of 10cm and 70cm

Zielflug [23.3K]

Answer:

The cost of 10 cm and 70 cm are £0.55 and £3.85 respectively.

Step-by-step explanation:

Material for a dress costs £5.50 per meter.

We know that, 1 meter = 100 cm.

Suppose, the cost of 10 cm material is $x$ and the cost of 70 cm material is $y$

Now, according to the ratio of "cost" to the "length of material" , we will get.......

$\frac{x}{10} =\frac{5.50}{100}\\ \\ 100x=10*5.50=55\\ \\ x=\frac{55}{100}=0.55$

and

$\frac{y}{70} =\frac{5.50}{100}\\ \\ 100y=70*5.50=385\\ \\ x=\frac{385}{100}=3.85$

So, the cost of 10 cm material is £0.55 and the cost of 70 cm material is £3.85

5 0

3 years ago

Find the size of angle YZX

Tasya [4]

Answer:

21.001 cm

Step-by-step explanation:

The diagram shows right triangle with

Hypotenuse ZY = 22.3 cm

Leg XY = 7.5 cm

By the Pythagorean theorem,

$XY^2+XZ^2=ZY^2\\ \\7.5^2+XZ^2=22.3^2\\ \\XZ^2=22.3^2-7.5^2\\ \\XZ^2=(22.3-7.5)(22.3+7.5)\\ \\XZ^2=14.8\cdot 29.8\\ \\XZ^2=441.04\\ \\XZ=\sqrt{441.04}\approx 21.001\ cm$

3 0

3 years ago

(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t<00≤t<11≤t<7t≥7;f(t)={0,t<0−5,0≤t<1−6,1≤t<76,t≥7; 1. wr

sergij07 [2.7K]

$f(t)=\begin{cases}0&\text{for }t$

Recall that

$u(t)=\begin{cases}0&\text{for }t$

Take it one piece at a time. For $t\ge0$ , we can scale $u(t)$ by -5:

$-5u(t)=\begin{cases}0&\text{for }t$

If we shift the argument by 1 and scale by -5, we have

$-5u(t-1)=\begin{cases}0&\text{for }t$

so if we subtract this from $-5u(t)$ , we'll end up with

$-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t$

For the next piece, we can add another scaled and shifted step like

$-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

so that

$-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

For the last piece, we add one more term:

$6u(t-7)=\begin{cases}0&\text{for }t$

and so putting everything together, we get $f(t)$ :

$f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)$
$f(t)\equiv-5u(t)-u(t-1)+12u(t-7)$

5 0

3 years ago

Could use some help with this math xl problem ​

Could use some help with this math xl problem