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dusya [7]
3 years ago
9

Y=6x-4 y=4x+2 substitution pls help plsplslsl​

Mathematics
2 answers:
djyliett [7]3 years ago
8 0

Answer: x=3,y=14

Step-by-step explanation:

tiny-mole [99]3 years ago
4 0

Answer:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:  ( 3 , 14 )

Equation Form:  x  =  3 , y  =  14

Step-by-step explanation:

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I dont get this question​ please help meeee
earnstyle [38]
The answer for this is 60
6 0
3 years ago
Solve the following linear system by graphing <br> 4x+5y=10<br> 3x-3y=21
Inga [223]

Answer:

y = 2

x = 5

Step-by-step explanation:

4x + 5y = 10 | ×3 |

3x - 3y = 21 | ×4 |

12x + 15y = 30

12x - 12y = 84

____________--

27y = -54

y = -54/27

y = 2

4x + 5y = 10 | ×3 |

3x - 3y = 21 | ×5 |

12x + 15y = 30

15x - 15y = 105

____________+

27x = 135

x = 135/27

x = 5

6 0
3 years ago
According to Boyle’s law, PV= K, what was the volume at the time of the first measurement given the following information? Round
Temka [501]
<h2>Hello!</h2>

The answer is:

The first measurement of volume is equal to 835.23 mL.

<h2>Why?</h2>

Boyle's Law equation can be used when the temperature is kept constant, and it establishes a relation between the pressure and volume, showing that when an ideal gas is kept constant, the pressure and volume are inversely proportional.

So, we Boyle's Law equation states that:

P_{1}V_{1}=P_{2}V_{2}

Where,

P_1=FirstPressure\\V_1=FirstVolume\\P_2=NewPressure\\V_2=NewVolume

Now, if we are looking for the first volume measurement, we need to rewrite the equation as follow:

P_{1}V_{1}=P_{2}V_{2}\\\\V_{1}=\frac{P_{2}V_{2}}{P_{1}}

So, substituting the given information and calculating, we have:

V_{1}=\frac{8.59atm*527mL}{5.42atm}

V_{1}=\frac{4526.93atm.mL}{5.42atm}=835.23mL

Hence, the first measurement of volume is equal 835.23 mL.

Have a nice day!

8 0
3 years ago
Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting
stealth61 [152]

Answer:

Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j} and refer attachment.

Step-by-step explanation:

Let the origin be the point 1 from where Ann start walking.

Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,

Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)

Ann walk as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}

Thus, Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}

 




7 0
3 years ago
Read 2 more answers
A local car dealer claims that 25% of all cars in San Francisco are blue. You take a random sample of 600 cars in San Francisco
sammy [17]

Answer:

No, we can't reject the dealer's claim with a significance level of 0.05.

Step-by-step explanation:

We are given that a local car dealer claims that 25% of all cars in San Francisco are blue.

You take a random sample of 600 cars in San Francisco and find that 141 are blue.

<u><em>Let p = proportion of all cars in San Francisco who are blue</em></u>

SO, Null Hypothesis, H_0 : p = 25%   {means that 25% of all cars in San Francisco are blue}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of all cars in San Francisco who are blue is different from 25%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 600 cars in San Francisco who are blue =   \frac{141}{600} = 0.235

            n = sample of cars = 600

So, <u><em>test statistics</em></u>  =  \frac{0.235-0.25}{{\sqrt{\frac{0.235(1-0.235)}{600} } } } }

                               =  -0.866

<em>Now at 0.05 significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that 25% of all cars in San Francisco are blue which means the dealer's claim was correct.

4 0
3 years ago
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