X^2+2x^2-5x
((x^2)+2x^2)-5x
Pull the factors out
3x^2-5x=x(3x-5)
x(3x-5)
x(3x-5)*5x^2
5x(3x-5)*x^2
Final
5x^3*(3x-5)
Answer:
Step-by-step explanation:
There are two consecutive positive even integers such that the square of the first is 364 more than five times a second. What are the two numbers?
Two consecutive year positive integers are represented by
x and x + 1
First integer = x
Second integer = y
There are two consecutive positive even integers such that the square of the first is 364 more than five times a second.
This is represented mathematically as:
x² = 364 + 5(x + 1)
x² = 364 + 5x + 5
x² -5x -5 - 364
x² - 5x - 369
Answer:
30
Step-by-step explanation:
the factors are 1,2,3,5,6,10,15,30
