Answer:
Step-by-step explanation:
eight less then the product of a number and 2
" the product " means multiply
the product of a number and 2.......2x
eight less....-8
2x - 8 <=== ur expression
First of all, remember what the equation of a line is:

Where:
m=slope
b=y-intercept.
Given this information, we can start by plugging in what we know, we are given the slope which is 2 so we can fill that in, remember m=slope

To find b, think about what your (x,y) point means:<span>(14,3). When x of the line is 14, y of the line must be 3.
Because we were given the point (14,3)
</span>
We need to find the value of b. The 2 is already set and x and y are variables. We want the equation for the line that specifically passes through the given point (14,3).
<span>Plug in for x the number 14 and for y the number 3:
</span>(14,3).
y=mx+b or 3=2 × 14+b,
solving for b: b=3-(2)(14). b=-25.
<span>Plug that in for b:
</span><span>y=2x-25
<span>Final answer:
</span><span>y=2x-25</span></span><span><span>
</span></span>
Answer:
the answer for your question is b
Answer:
Step-by-step explanation:
It's like the same thing for adding. For example if you have 3 x 4. You can add 3 four times or you can add 4 three times. Like this.
3 + 3 + 3 + 3 = 12 because you know 3 + 3 =6 and 6 + 6 equals 12.
OR
4 + 4 + 4 = 12 because you know 4 + 4 = 8 and 8 + 4 equals 12.
I hope this helped. I am sorry if I didn't do much of help. Have a wonderful day.
Answer:
Step-by-step explanation:
Hello!
The variable of interest is
X: hourly wage of a high school student
X~N(μ;σ²)
X[bar]= $8.25
σ= $0.25
For a 95% CI for the average hourly wage for<u> 1 </u>high school student:
For this exercise you have to consider the sample size n=1
a) The margin of error of the CI is calculated as:
d=
* σ
1-α: 0.95 ⇒ α:0.05
1-α/2:0.975

d= 1.96 * 0.25= 0.49
b)
The formula for the interval is
X[bar] ±
* σ
[8.25 ± 0.49]
[7.76; 8.74]
With a 95% you'd expect the interval $[7.76; 8.74] to include the average hourly wage of one high school student in Illinois.
c)
Te calculated interval is $ [7.76; 8.74] the value $9.15 does nor fall within that acceptable range.
I hope this helps!