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padilas [110]
3 years ago
10

PLSSS HELP IF YOU TURLY KNOW THISS

Mathematics
1 answer:
andrey2020 [161]3 years ago
7 0

Answer:

x = \frac{1}{3}

Step-by-step explanation:

The bar above the 3 indicates the 3 is a repeating digit , that is

0.3333....

We require 2 equations with the repeating digit placed after the decimal point

let x = 0.3333... (1)

Multiply both sides by 10 )

10x = 3.3333... (2)

Subtract (1) from (2) thus eliminating the repeating digits

9x = 3 ( divide both sides by 9 )

x = \frac{3}{9} = \frac{1}{3}

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Can someone help me answer this?
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Answer:

x = 40 , y = 70

Step-by-step explanation:

y = 70°

x° = 180° - 2 × 70° = 40°

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If the risk-free rate is 7 percent, the expected return on the market is 10 percent, and the expected return on Security J is 13
Lelu [443]

Answer:

0.02 or 2% = Beta

Step-by-step explanation:

Given that,

Risk-free rate = 7 percent

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Therefore, the beta of Security J is calculated as follows;

Expected return on Security J = Risk-free rate + Beta (Expected return on the market - Risk-free rate)

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3 years ago
Suppose a couple planned to have three children. Let X be the number of girls the couple has.
sesenic [268]

Answer:

a) {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) {0,1,2,3}

c)

P(X=2) = \dfrac{3}{8}

d)

P(\text{3 boys}) = \dfrac{1}{8}

Step-by-step explanation:

We are given the following in the question:

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

a) possible arrangements of girls and boys

Sample space:

{GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) sample space for X

X is the number of girls couple has. Thus, X can take the values 0, 1, 2 and 3 that is 0 girls, 1 girl, 2 girls and three girls from three children.

Sample space: {0,1,2,3}

c) probability that X=2

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That is we have to compute the probability that couple has exactly two girls.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

Favorable outcome: {GGB, GBG, BGG}

P(X=2) =\dfrac{3}{8}

d) probability that the couple have three boys.

Favorable outcome: {BBB}

P(BBB) = \dfrac{1}{8}

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Because

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Answer:

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