The length of a curve <em>C</em> parameterized by a vector function <em>r</em><em>(t)</em> = <em>x(t)</em> i + <em>y(t)</em> j over an interval <em>a</em> ≤ <em>t</em> ≤ <em>b</em> is
In this case, we have
<em>x(t)</em> = exp(<em>t</em> ) + exp(-<em>t</em> ) ==> d<em>x</em>/d<em>t</em> = exp(<em>t</em> ) - exp(-<em>t</em> )
<em>y(t)</em> = 5 - 2<em>t</em> ==> d<em>y</em>/d<em>t</em> = -2
and [<em>a</em>, <em>b</em>] = [0, 2]. The length of the curve is then
Answer:
33600 m²
Step-by-step explanation:
The top and bottom horizontal sides are parallel, so this is a trapezoid with bases DC and AB. The height is BC.
area of trapezoid = (a + b)h/2
where a and b are the lengths of the bases, and h is the height.
We need to find the height, BC.
Drop a perpendicular from point A to segment DC. Call the point of intersection E. E is a point on segment DC.
DE + EC = DC
EC = AB = 360 m
DC = 600 m
DE + 360 m = 600 m
DE = 240 m
Use right triangle ADE to find AE. Then BC = AE.
DE² + AE² = AD²
DE² + 240² = 250²
DE² = 62500 - 57600
DE² = 4900
DE = √4900
DE = 70
BC = 70 = h
area = (a + b)h/2
area = (600 m + 360 m)(70 m)/2
area = 33600 m²
Answer:
.03
Step-by-step explanation:
.03 would be 3% where all the others are 30% hope this helped!
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