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lina2011 [118]
3 years ago
5

Keenan worked at an ice cream shop. One day, he counted the first 8

Mathematics
1 answer:
ZanzabumX [31]3 years ago
8 0

Answer:

2

Step-by-step explanation:

correct me if i'm wrong

la la la

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The sale price of an item is $160 after a 20% off discount. What was the original price of the item?
bulgar [2K]

Answer:

200

Step-by-step explanation:

160/80 is 2. 2 times 100 is 200

6 0
3 years ago
Find the area of the figure <br><br> PLEASE HELP
Bad White [126]

Answer:

I Got You 64 is the correct answer.

Step by-step explanation:

7 x 2= 14

5 x 10= 50

50 + 14= 64

Give 5 stars, Smash that thanks button and give brainlyest.

And dont forget having a bad day change it. Bye!

6 0
3 years ago
For a back to school sale the price of a calculator is reduceded from 70% to $59.50. What is the answer
Leona [35]
Thats what i came up with $25.50
7 0
3 years ago
While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
4 years ago
Marcella dived 40.8 gallons of paint among 8 coontainer How much paint is in each container
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5.1gallons is in each container

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3 years ago
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