S = 1 + 3 + 5 + ... + 11 + 13 + 15
S = 15 + 13 + 11 + ... + 5 + 3 + 1
==> 2S = (1 + 15) + (3 + 13) + (5 + 11) + ... + (15 + 1)
There are 8 terms in the sum, so
2S = 8 * 16 = 128
S = 128/2 = 64
Answer:
6 units
Step-by-step explanation:
The distance between two points can be calculated with the formula
However, since (0, 2) and (0, 8) have the same x coordinate of 0, the distance between them is the difference in their y-coordinates.
Distance between (0, 2) and (0, 8)
= 8 -2
= 6 units
They are all integers so...
first lets substitute
A.3x=13
X=13/3
b.3x+2=13
3x=11
x=11/3
c.3x+4=13
3x=9
x=3
d.3x+6=13
3x=7
x=7/3
E.3x+8=13
3x=5
x=5/3
therefore the possible is letter c because it must be an integer and the definition of integer states that it is not a decimal nor a fraction
The answer you want would be C.52
Reason: 32+5= 37 that is the 1st and 2nd term. 37+5=42 thatis the 3rd term. 42+5=47 that's the 4th term. And 47+5=52 that's the 5th term.
Hope it helps!!
Answer:
5 units
Step-by-step explanation:
