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Aleks [24]
3 years ago
12

Can you help me in this one please I don’t understand

Mathematics
1 answer:
Artemon [7]3 years ago
4 0

Answer:

x = 2 and y = 0

So the answer is c (2,0)

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How many significant figures does the measurement 1.50 have?
Aleks [24]

Answer:

22+54

Step-by-step explanation:

5+3

7 0
3 years ago
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An equation is 18=0.32 multiplied by w
castortr0y [4]
So whats the question? Sorry im confused
7 0
4 years ago
Write an equation for the line parallel to the given line that contains C. <br> C (1,8); 5/7x + 7
Genrish500 [490]

-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{y = 5/7x + 51/7}

-------------------------------------------------------------------------------------------------------------

Given: \textsf{Goes through (1, 8) and is parallel to y = 5/7x + 7}

Find:  \textsf{Write an equation that follows that criteria}

Solution: We know that our equation is going to parallel to the line that was given therefore the slope would stay the same at 5/7.  We also have a point so we can plug in the values into the point-slope form, distribute, and solve for y.

<u>Plug in the values</u>

  • \textsf{y - y}_1\textsf{ = m(x - x}_1\textsf{)}
  • \textsf{y - 8 = 5/7(x - 1)}

<u>Distribute</u>

  • \textsf{y - 8 = (5/7 * x) + (5/7 * (-1))}
  • \textsf{y - 8 = 5/7x - 5/7}

<u>Add 8 to both sides</u>

  • \textsf{y - 8 + 8 = 5/7x - 5/7 + 8}
  • \textsf{y = 5/7x - 5/7 + 8}
  • \textsf{y = 5/7x + 51/7}

Therefore, the final equation that follows the description that was provided in the problem statement is y = 5/7x + 51/7.

4 0
2 years ago
Travis bought two plots of land at the beginning of 2000. When purchased, the smaller plot of land was valued at $20,000.00 and
stepan [7]
HAT MATH ARE U IN
i got part of it but it lost me the 
<span>differ part of land is 49,500 but it lost meh hope it helps gl</span>
3 0
3 years ago
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Imagine you had 40 one-metre sections of fencing.
Darya [45]

Answer: If I’m not mistaken, the largest area is 75 m2 and the smallest is 2 m2

Step-by-step explanation:

For both : since they are asking for the area, you should calculate the perimeter.

So for the largest area, since you know that you have 40 fences, and each are 1 meter long, and they’re also asking for the largest rectangular area, this means that only the opposite sides will have the same length, so in order to divide the rectangle with the 40 one-meter fences, the biggest sides have to be 15 meters long (so for both : 15x2=30 meters). Then you deduct from 40, 30 : 40-30 = 10 which then you can devide by 2 and find 5 + 5 and that means that the 2 smallest sides will be 5 meters long each. Then finally to calculate the perimeter you should do the biggest side multiplied by the smallest side : 15 x 5 and you find 75 m2 (squaremeters), if I’m not mistaken.

And for the smallest area you take the smallest possibilities knowing that only the opposite sides should have the same length and not all of them, so you do 1 x 2 and you find 2 m2.

8 0
4 years ago
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