Rewrite the expression in factored form. If you get stuck, try drawing a diagram. x^2−28x−60

Mathematics

2 answers:

il63 [147K]3 years ago

8 0

Answer:

(x - 30)(x + 2)

Step-by-step explanation:

il63 [147K]3 years ago

4 0

(X-30) (x+2) is the answer

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Solve this system of equations using substitution. Put your answer in ordered pair form, (x,y).

Gelneren [198K]

2x + 5y = 2
-3x - y =-3

-3x - y = -3
y = 3x - 3

substitute y = 3x - 3 into the first equation.

2x + 5y = 2
2x + 5(3x - 3) = 2
2x + 15x - 15 = 2
17x - 15 = 2

solve for x in 17x - 15 = 2

17x - 15 = 2
17x = 2 + 15
17x = 17
x = 1

substitute x = 1 into y = 3x - 3

y = 3x - 3
y = 3(1) - 3
y = 3 - 3
y = 0

(1, 0) << the answer

hope this helped, God bless!

8 0

3 years ago

A. Ana bought a table having an area of

Anna35 [415]

Answer:

The side length of the table is x + 5

Step-by-step explanation:

To solve this, you need only take the square root of the area:

$\sqrt{x^2 + 10x + 25}\\= \sqrt{(x + 5)^2}\\= x + 5$

So the side length of the table is x + 5

7 0

3 years ago

Find the area of the region that lies inside the first curve and outside the second curve. r = 6 − 6 sin θ, r = 6

yan [13]

Each curve completes one loop over the interval $0\le t\le2\pi$ . Find the intersections of the curves within this interval.

$6-6\sin\theta=6\implies 1-\sin\theta=1\implies \sin\theta=0\implies \theta=0,\theta=\pi$

The region of interest has an area given by the double integral

$\displaystyle\int_\pi^{2\pi}\int_6^{6-6\sin\theta}r\,\mathrm dr\,\mathrm d\theta$

equivalent to the single integral

$\displaystyle\frac12\int_\pi^{2\pi}\bigg((6-6\sin\theta)^2-6^2\bigg)\,\mathrm d\theta$

which evaluates to $9\pi+72$ .