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vivado [14]
2 years ago
13

What’s 5x9? Lol Id k

Mathematics
2 answers:
alekssr [168]2 years ago
6 0

Answer:

5 x 9 = 45

Step-by-step explanation:

Vedmedyk [2.9K]2 years ago
4 0

Answer:

Step-by-step explanation:

25

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What is the square root of 8y to the 7th power
kaheart [24]

It would be 2 square root of 2 and y7 square root. It's two parts to the answer. 
8 0
3 years ago
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For the given pair of events A and B, complete parts (a) and (b) below.
steposvetlana [31]

Answer:

(a) Option A. independent

(b) P(A\ and\ B) = 0.0312

Step-by-step explanation:

Two events A and B are considered dependent if the occurrence of one affects the probability of occurrence of another.

In this case, the events are independent because the birth of a girl or a boy does not affect the probability of obtaining a 1 by throwing a 16-sided die.

In the same way, throwing a die and obtaining the number 1 does not affect the probability that a baby is a girl or a boy.

When two events are independent then

P(A\ and\ B) = P(A)*P(B)

The probability that a baby is a girl is

P(A) = 0.5

The probability of obtaining a 1 when casting a 16-sided die is:

P(B) = \frac{1}{16}

Then:

P(A\ and\ B) = 0.5 * \frac{1}{16}

P(A\ and\ B) = 0.0312

5 0
3 years ago
use Taylor's Theorem with integral remainder and the mean-value theorem for integrals to deduce Taylor's Theorem with lagrange r
Vadim26 [7]

Answer:

As consequence of the Taylor theorem with integral remainder we have that

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \int^a_x f^{(n+1)}(t)\frac{(x-t)^n}{n!}dt

If we ask that f has continuous (n+1)th derivative we can apply the mean value theorem for integrals. Then, there exists c between a and x such that

\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}dt = \frac{f^{(n+1)}(c)}{n!} \int^a_x (x-t)^n d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{n+1}}{n+1}\Big|_a^x

Hence,

\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{(n+1)}}{n+1} = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1} .

Thus,

\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}

and the Taylor theorem with Lagrange remainder is

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}.

Step-by-step explanation:

5 0
3 years ago
If pqr= 1 show that 1/(1+p+q^-1)+1/(1+q+r^-1)+1/(1+r+p^-1) = 1.<br>​
mariarad [96]

Answer:

1

Step-by-step explanation:

1/(1+p+q^-1)+1/(1+q+r^-1)+1/(1+r+p^-1) = 1.

7 0
2 years ago
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Write the population of Florida in expanded formusing exponents <br><br> 18,801310
Tju [1.3M]
10,000,000+
8,000,000+800,000+1,000+300+10
7 0
3 years ago
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