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kolbaska11 [484]
2 years ago
15

Simplify 2(2.036)-2.268​

Mathematics
1 answer:
iren2701 [21]2 years ago
6 0
The answer is 1.804 hope it helps
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How would i graph this equation y=3x+1
Kipish [7]

Answer:

(0,1)(1,4)

Step-by-step explanation:

Put in any value of x to find y, then you have a coordinate, then plot it

lets say i pick 0 for x

y = 3(0) + 1

y = 1

(0,1)

lets say i also pick 1 for x

y = 3(1)+1

y = 4

You need atleast two points to plot a line, these are two points.

6 0
3 years ago
Round to the nearest thousand and then add the rounded numbers. <br><br> 8794<br> +312
lyudmila [28]

Answer:

4.0148 rounded to the nearest thousand is 0, but if you meant rounded to the nearest thousandth, it would be 4.015 because the 8 in the ten thousandth column would cause the 4 in the thousandth column to round up to 5.

Step-by-step explanation:

7 0
3 years ago
Please help me guys I need ur help
Alexeev081 [22]

Answer:

3.5 yr

Step-by-step explanation:

np ;)

8 0
3 years ago
Read 2 more answers
Which expression is equivalent to log w (x2-6)4
natka813 [3]
Log w (x^2-6)^4

Using log a b = log a + log b, with a=w and b=(x^-6)^4:
log w (x^2-6)^4 = log w + log (x^2-6)^4

Using in the second term log a^b = b log a, with a=x^2-6 and b=4
log w (x^2-6)^4 = log w + log (x^2-6)^4 =  log w + 4 log (x^2-6)

Then, the answer is:
log w (x^2-6)^4 = log w + 4 log (x^2-6)
7 0
3 years ago
Read 2 more answers
In how many ways can five children posing for a photograph line up in a row?
Shtirlitz [24]

Answer:

number of ways = 120

Step-by-step explanation:

The number of ways five children can pose for a photograph line up in a row is given by the number of permutations of 5 elements in 5 different positions (positions in the line), then

number of ways = number of permutations of 5 elements = 5! = 5 * 4 * 3 * 2 * 1 = 120

Since the first children that occupies the line can be on any of the positions (5 positions) , but then the second one can choose any of the 4 remaining positions (since the first children had already occupied one) , the third can choose 3 ... and so on.

5 0
3 years ago
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