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zavuch27 [327]
2 years ago
6

The length of a rectangular book is 2 times its width. The perimeter of the book is 42 inches. Write a system of

Mathematics
1 answer:
wel2 years ago
7 0

Answer:

Mark me as brainlist

Step-by-step explanation:

P = Perimeter            

L = Length          

W = Width

Perimeter of rectangle = L + L + W + W        

or P = 2L + 2W

You know:

P = 36 inches

L = 2W          [length is(=) 2 times it's width]

W = ?

P = 2L + 2W    

Substitute/plug in what you know, plug in 2W for L since L = 2W

36 = 2(2W) + 2W         Simplify

36 = 4W + 2W

36 = 6W        Divide 6 on both sides

6 = W              Now that you know the width, you can find the length:

L = 2W

L = 2(6)

L = 12

L = 12 in

W = 6 in

PROOF

P = 2(12) + 2(6)

P = 24 + 12

P = 36

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3 years ago
Simplify each problem and expre<br> 1) (2 x 10°) + (5 x 109)
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<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Answer:

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3 0
3 years ago
What is the true solution to 2 in e^in 5x = 2 in 15
Mkey [24]
We have to solve this equation:
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7 0
3 years ago
Read 2 more answers
Cos^3a-sin^3a/cosa-sina
KIM [24]

Answer:

1 + cosa sina

Step-by-step explanation:

\frac{cos^3a-sin^3a}{cosa-sina}

cos³a - sin³a ← is a difference of cubes and factors in general as

a³ - b³ = (a - b)(a² + ab + b²) , then

cos³a - sin³a

= (cosa - sina )(cos²a + cosa sina + sin²a)

= (cosa - sina)(1 + cosa sina) [ sin²a + cos²a = 1 ]

Then

\frac{cos^3a-sin^3a}{cosa-sina}

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8 0
1 year ago
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