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3 years ago

The length of a rectangular book is 2 times its width. The perimeter of the book is 42 inches. Write a system of

Mathematics

1 answer:

wel3 years ago

7 0

Answer:

Mark me as brainlist

Step-by-step explanation:

P = Perimeter

L = Length

W = Width

Perimeter of rectangle = L + L + W + W

or P = 2L + 2W

You know:

P = 36 inches

L = 2W [length is(=) 2 times it's width]

W = ?

P = 2L + 2W

Substitute/plug in what you know, plug in 2W for L since L = 2W

36 = 2(2W) + 2W Simplify

36 = 4W + 2W

36 = 6W Divide 6 on both sides

6 = W Now that you know the width, you can find the length:

L = 2W

L = 2(6)

L = 12

L = 12 in

W = 6 in

PROOF

P = 2(12) + 2(6)

P = 24 + 12

P = 36

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3 years ago

A patient has 0.0000075 gram of iron in 1 liter of blood. The normal level is between 6* 10^-7 grams and 1.6*10^-5 grams. Is the

Vinil7 [7]

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and it has to be between 0.0000006 and 0.000016

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3 years ago

What do I multiple to -1 1/7 to get 1

Setler79 [48]

Answer:

-7/8

Step-by-step explanation:

-1 1/7 is in improper fraction form -8/7

-8/7x = 1

x = -7/8

7 0

3 years ago

Question 2 (multiple choice)

castortr0y [4]

Your x-intercept is at (-2,0) and your y intercept at (0,-3), so it's D

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3 years ago

Which statement describes if there is an extraneous solution to the equation √x-3 = x-5? A. there are no solutions to the equati

Brrunno [24]

Remember that an extraneous solution of an equation, is the solution that emerges from solving the equation but is not a valid solution.

Lets solve our equation to find out what is the extraneous solution:
 $\sqrt{x-3} =x-5$
$(\sqrt{x-3})^2 =(x-5)^2$
$x-3=x^2-10x+25$
$x^2-11x+28=0$
$(x-4)(x-7)=0$
$x-4=0$ and $x-7=0$
$x=4$ and $x=7$

So, the solutions of our equation are $x=4$ and $x=7$ . Lets replace each solution in our original equation to check if they are valid solutions:
- For $x=7$
$\sqrt{x-3} =x-5$
$\sqrt{7-3} =7-5$
$\sqrt{4} =2$
$2=2$
We can conclude that 7 is a valid solution of the equation.

- For $x=4$
$\sqrt{x-3} =x-5$
$\sqrt{4-3} =4-5$
$\sqrt{1} =1$
$1 \neq 1$
We can conclude that 4 is not a valid solution of the equation; therefore, 4 is a extraneous solution.

We can conclude that the correct answer is: D. the extraneous solution is x = 4

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3 years ago