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Drupady [299]
3 years ago
14

Help with this question please please please

Mathematics
1 answer:
Anna35 [415]3 years ago
5 0

Answer:

1900 miles long

Step-by-step explanation:

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PLEASE HELP<br> 2!/0!=<br> 0<br> 2<br> undefined
GuDViN [60]

Answer:

2

Step-by-step explanation:

any expression divided by 1 remains the same

you can also calculate the factorial

6 0
3 years ago
S = ut+ 16t²<br>Find the value of s when u = 2 and t = 3.​
Fed [463]

Answer:

<h2>150</h2>

Step-by-step explanation:

Given,

u = 2

t = 3

Now, Finding the value of s

s = ut \:  + 16 {t}^{2}

Plugging the values of u and t

s = 2 \times 3 + 16 \times  {( 3)}^{2}

Calculate

s = 2 \times 3 + 16 \times 9

s = 6 + 144

Calculate the sum

s = 150

Hope this helps ..

Good luck on your assignment..

4 0
3 years ago
Read 2 more answers
Tricia listed her assets and liabilities.
kumpel [21]

Answer:

<u>The correct answer is A. Credit card bill and B. Car loan</u>

Step-by-step explanation:

Let's recall that we consider a personal or familiar liability an obligation to pay money you or your family owe to another person or financial institution like a bank. Liabilities can be classified according to the term, either short such as a credit card or loan from the bank with one-year term, or long such as a car loan or mortgage.

According to that definition, Tricia's liabilities are A. Credit card bill and B. Car loan.

6 0
4 years ago
Read 2 more answers
Suppose that, in 1995, the weight of 16-year old males in the United States was normally distributed with a mean of 143 lbs and
seropon [69]

Answer:

Step-by-step explanation:

The null hypothesis is:

H0: μ(1995)=μ(2019)

The alternative hypothesis is:

H1: μ(1995)<μ(2019)

Because Roger wants to know if mean weight of 16-old males in 2019 is more than the mean weight of 16-old males in 1995 the test only uses one tail of the z-distribution.  It is not a  two-sided test because in that case the alternative hypothesis would be:  μ(1995)≠μ(2019).

To know the p-value, we use the z-statistic, in this case 1.89 and the significance level. Because the problem does not specify it, we will search for the p-value at a 5% significance level and at a 1%.

For a z of 1.89 and 5% significance level, the p-value is: 0.9744

For a z of 1.89 and 1% significance level, the p-value is: 0.9719

4 0
3 years ago
Worker A can finish a job in
Oksi-84 [34.3K]

Answer:

4

Step-by-step explanation:

\frac{1}{2}  -  \frac{1}{3} \\  \\  =  \frac{1}{6}  \times 24 \\  = 4

8 0
3 years ago
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