Answer:
The equation of the Parallel line to the given line is 5x+y-7=0
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given that the line y = - 5x+4 and point (1,2)
The equation of the Parallel line to the given line is ax+by+k=0
Given straight line 5x + y -4 =0
The equation of the Parallel line to the given line is 5x+y+k=0
This line passes through the point (1,2)
5x+y+k=0
5(1)+2+k=0
⇒ 7+k=0
k =-7
<u>Final answer:-</u>
The equation of the Parallel line to the given line is 5x+y-7=0
Reflection line of reflection y=2
Not too sure could be rotation maybe
Answer:
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Step-by-step explanation:

Actually, there would be no solution because the w's cancel out so that leaves -6=-9 and that is not true.