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Charra [1.4K]
3 years ago
13

The drawing shows a collision between 2 pucks on an air-hockey table. Puck A has a mass of 0.0380 kg and is moving along the x a

xis with a velocity of + 6.29 m/s. It takes a collision with puck B, which has a mass of 0.0760 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with pluck A at an angle of 65 degrees to the x axis and pluck B at an angle of -37 degrees to the x axis. Find the speed of pluck A and pluck B.
Physics
1 answer:
masya89 [10]3 years ago
6 0

Answer:

basic question youre a mo-orn

Explanation:

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Reacting with water in an acidic solution at a particular​ temperature, compound A decomposes into compounds B and C according t
Diano4ka-milaya [45]

Answer:

after  t = 3 hours compound A remain 0.396 M

t = 12.98 hours

Explanation:

P = P_0*e^(-kt)  

t = 30 minutes = 30/60 hours = 0.5 hours

and P_0 = 0.60M

and P after t = 0.5 hours is 0.56 M

(0.56/0.6) = e^(-kt)

0.933 =e^(-kt)

k = 0.138

P = P_0*e^(-0.138t)

Now after  t = 3 hours,

P = 0.6* e^((-0.138)*3) = 0.396 M

time  when P = 0.1 M

0.1 = 0.6*e^(-0.138t)

t = 12.98 hours

8 0
3 years ago
In your own words explain why the thickness and length of a wire could effect the flow of electrons​
agasfer [191]

Answer:

(you can use my exact words) The length and thickness would make it so that the electrons move differently than they would a shorter and thinner wire because with the wire being longer the electrons would have a longer trip and with the wire being thicker the electrons would be more spread out and move be able to move more freely

8 0
3 years ago
A car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 22 ft/s2. What is the dist
makvit [3.9K]

Answer:

The correct solution is "122.2211".

Explanation:

Given:

deceleration,

a = 22 ft/sec²

Initial velocity,

V_i=50 \ m/h

Now,

V_i=50 \ m/h\times 5280 \ ft/m\times hr/3600 \ s

    =73.333 \ ft/sec

Now,

Final velocity,

V_f=0

Initial velocity,

V_{initial} = 73.333 \ ft/sec

hence,

⇒ V_f^2=V_i^2+2aD

By putting the values, we get

      0=(73.333)^2+2\times( -22) D

  44D=(73.333)^2

      D=\frac{(73.333)^2}{44}

          =122.2211

3 0
3 years ago
PLEASE HELP ASAP
DaniilM [7]

Your answers:

Q1. I don't have information on her situation, but an EMR is a medical record that is stored digitally in a secure computer database within an organization or healthcare system. This system allows electronic storage, retrieval, and modification of medical records, and is an alternative to traditional, paper medical records.

Q2. Their food proportions, do they eat every meal, do they eat their vegetables, fruits grains, protein, etc. Check for healthy and unhealthy habits of eating and exercise.  Additional notes on medical problems relating to food concerns you may have to look further into based on her answers.

Q3. The info isn't provided,  but what I do know is that detection requires awareness of risk factors for, and symptoms and signs of, anorexia nervosa (e.g., participation in activities valuing thinness, family history of an eating disorder, amenorrhea, lanugo hair) and bulimia nervosa (e.g., unsuccessful attempts at weight loss, history of childhood sexual abuse, family history of depression, erosion of tooth enamel from vomiting, parotid gland swelling, and gastroesophageal reflux). Providers must also remain alert for disordered eating in female athletes (the female athlete triad) and disordered eating in diabetics. Treatment requires a multidisciplinary team including a primary care practitioner, nutritionist, and mental health professional. The role of the primary care practitioner is to help determine the need for hospitalization and to manage medical complications (e.g., arrhythmias, refeeding syndrome, osteoporosis, and electrolyte abnormalities such as hypokalemia).

I'm sorry I cannot answer all your questions because there's a typing limit. :)

Thank you for your patience, and I hope I helped!

Would appreciate Brainliest ;)

4 0
3 years ago
How fast must an object move before its length appears to be contracted to one-fourth its proper length? (Give your answer in te
Tresset [83]

Answer:

<em>0.97c</em>

<em></em>

Explanation:

From the relativistic equation for length contraction, we have

l = l_{0}\sqrt{1 - \beta }

where

l is the final length of the object

l_{0} is the original length of the object before contraction

β = v^{2} /c^2

where v is the speed of the object

c is the speed of light in free space = 3 x 10^8 m/s

The equation can be re-written as

l/l_{0} = \sqrt{1 - \beta }

For the length to contract to one-fourth of the proper length, then

l/l_{0} = 1/4

substituting into the equation, we'll have

1/4 = \sqrt{1 - \beta }

substituting for β, we'll have

1/4 = \sqrt{1 - v^2/c^2 }

squaring both side of the equation, we'll have

1/16 = 1 - v^2/c^2

v^2/c^2 = 1 - 1/16

v^2/c^2 = 15/16

square root both sides of the equation, we have

v/c = 0.968

v = <em>0.97c</em>

3 0
3 years ago
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