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2 years ago

1)what is the definition of moment of inertia?

Physics

2 answers:

OLEGan [10]2 years ago

3 0

Answer:

Moment of inertia is the inertia of a rotating body with respect to its rotation. So basically it's the object's resistance to a rotational acceleration. This relates to Newton's first law! What does that exactly mean? Let's check out the explanation.

One formula that it is written in is I= mr $x^{2}$

Explanation:

As Bill Nye says, "Inertia is a property of matter. Objects that are not moving don't move unless they get pushed or pulled. Moving objects keep moving unless they get pushed or pulled. This feature of objects and materials is what we call inertia."

I would check out Dan Fullerton's concept

and Organic Chemistry

steposvetlana [31]2 years ago

3 0

Answer:

a quantity expressing a body's tendency to resist angular acceleration, which is the sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation.

In simpler terms Moment of inertia also called "angular mass" (kg. · m2), is the inertia of a rotating body with respect to its rotation. It is a rotating body's resistance to angular acceleration or deceleration, equal to the product of the mass and the square of its perpendicular distance from the axis of rotation.

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A uniform magnetic field is perpendicular to the plane of a circular loop of diameter 13 cm formed from wire of diameter 2.6 mm

I am Lyosha [343]

Answer:

Rate of change of magnetic field is $3.466\times 10^3T/sec$

Explanation:

We have given diameter of the circular loop is 13 cm = 0.13 m

So radius of the circular loop $r=\frac{0.13}{2}=0.065m$

Length of the circular loop $L=2\pi r=2\times 3.14\times 0.065=0.4082m$

Wire is made up of diameter of 2.6 mm

So radius $r=\frac{2.6}{2}=1.3mm=0.0013m$

Cross sectional area of wire $A=\pi r^2=3.14\times0.0013^2=5.30\times 10^{-6}m^2$

Resistivity of wire $\rho =2.18\times 10^{-8}m$

Resistance of wire $R=\frac{\rho L}{A}=\frac{2.18\times 10^{-8}\times 0.4082}{5.30\times 10^{-6}}=1.67\times 10^{-3}ohm$

Current is given i = 11 A

So emf $e=11\times 1.67\times 10^{-3}=0.0183volt$

Emf induced in the coil is $e=-\frac{d\Phi }{dt}=-A\frac{dB}{dt}$

$0.0183=5.30\times 10^{-6}\times \frac{dB}{dt}$

$\frac{dB}{dt}=3.466\times 10^3=T/sec$

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Explanation:

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