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horrorfan [7]
4 years ago
12

A Michelson interferometer uses light with a wavelength of 452.446 nm. Mirror M2 is slowly moved a distance x, causing exactly 2

.2700×102 bright-dark-bright fringe shifts to be observed starting and ending with a central bright spot. If the mirror moved only half the distance, what would the final image be?
a. Bright spot.

b. Dark spot.

c. In between bright and dark spots.

d. Impossible to determine, more information needed.
Physics
1 answer:
I am Lyosha [343]4 years ago
3 0

Answer:

Option b. Dark spot

Explanation:

Michelson interferometer gives the path difference of the light as path difference, d as twice the distance moved or covered by the mirror M_{2}, x and is given as:

d= 2x

Since, its an even multiple, we obtain a bright fringe

now, when the move half the distance, i.e., \frac{x}{2}

Therefore, the path difference for half the distance \frac{x}{2} is:

d = x

As it is clear that its an odd multiple which correspond to dark spot as the final image

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Speed of Dayshawn travelling towards his home is 12 m/s

Speed of her mom towards his school is 5 m/s

They both starts at same time so whenever they will meet on their path the sum of the distance covered by Dayshawn and distance covered by his mom must be equal to the total distance of school and home

Now let say they both meet after "t" time when they starts motion

so we can write the total distance between school and home as

d = v_1*t + v_2*t

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v_2 = 5 m/s = speed of his mom

now by solving the above equation

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A 2,300-kg truck is traveling down a highway at 32 m/s. What is the kinetic energy of the truck?
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