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3 years ago

Required information

Physics

1 answer:

cupoosta [38]3 years ago

4 0

Answer:

hi there is that OK for the weekend of the following week as well

Explanation:

6th of March is fine for me

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Consider a wire of a circular cross-section with a radius of R = 3.17 mm. The magnitude of the current density is modeled as J =

Sloan [31]

Answer:

The current is $I = 8.9 *10^{-5} \ A$

Explanation:

From the question we are told that

The radius is $r = 3.17 \ mm = 3.17 *10^{-3} \ m$

The current density is $J = c\cdot r^2 = 9.00*10^{6} \ A/m^4 \cdot r^2$

The distance we are considering is $r = 0.5 R = 0.001585$

Generally current density is mathematically represented as

$J = \frac{I}{A }$

Where A is the cross-sectional area represented as

$A = \pi r^2$

=> $J = \frac{I}{\pi r^2 }$

=> $I = J * (\pi r^2 )$

Now the change in current per unit length is mathematically evaluated as

$dI = 2 J * \pi r dr$

Now to obtain the current (in A) through the inner section of the wire from the center to r = 0.5R we integrate dI from the 0 (center) to point 0.5R as follows

$I = 2\pi \int\limits^{0.5 R}_{0} {( 9.0*10^6A/m^4) * r^2 * r} \, dr$

$I = 2\pi * 9.0*10^{6} \int\limits^{0.001585}_{0} {r^3} \, dr$

$I = 2\pi *(9.0*10^{6}) [\frac{r^4}{4} ] | \left 0.001585} \atop 0}} \right.$

$I = 2\pi *(9.0*10^{6}) [ \frac{0.001585^4}{4} ]$

substituting values

$I = 2 * 3.142 * 9.00 *10^6 * [ \frac{0.001585^4}{4} ]$

$I = 8.9 *10^{-5} \ A$

5 0

4 years ago

How do animals get the nitrogen they need<br>

Alenkinab [10]

Answer:

Animals get the nitrogen they need by eating plants or other animals that contain nitrogen.

Explanation:

4 0

3 years ago

Read 2 more answers

While filming an intense action sequence for the next James Bond movie, a controlled explosion detonates 1.3 km away from the ac

brilliants [131]

To solve this problem we must basically resort to the kinematic equations of movement. For which speed is defined as the distance traveled in a given time. Mathematically this can be expressed as

$v = \frac{d}{t}$

Where

d = Distance

t = time

For which clearing the time we will have the expression

$t = \frac{d}{v}$

Since we have two 'fluids' in which the sound travels at different speeds we will have that for the rock the time elapsed to feel the explosion will be:

$t = \frac{1300m}{3000m/s}$

$t = 0.433s$

In the case of the atmosphere -composite of air- the average speed of sound is 343m / s, therefore it will take

$t = \frac{1300m}{343m/s}$

$t = 3.79s$

The total difference between the two times would be

$\Delta t = 3.79s-0.433s$

$\Delta t = 3.357s$

Therefore 3.357s will pass between when they feel the explosion and when they hear it

8 0

4 years ago

Find the resultant of these two forces acting on a particle 50N and 40N<br>

Sauron [17]

{answer}
The 50N of force would pull the 40N of force, you’d have 10 N of extra force pulling the 40N to the 50N.

{ I hope this helps :) }

7 0

3 years ago

Need help best answer will get brainiest

solong [7]

Answer:

1) A trait is a specific feature or characteristic, typically genetic.

2) One trait that helps an animal survive is a Chameleon's camouflage. Camouflage helps the chameleon blend in with their surroundings to avoid a predator or to sneak up on prey.

Explanation:

6 0

3 years ago

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