Question

Newton's law of gravity and Coulomb's law are both inverse-square laws. Consequently, there should be a "Gauss's law for gravity." The electric field was defined as E⃗ =F⃗ onq/q , and we used this to find the electric field of a point charge. Using analogous reasoning, what is the gravitational field g⃗ of a point mass? Write your answer using the unit vector r^ , but be careful with signs; the gravitational force between two "like masses" is attractive, not repulsive. Express your answer in terms of the variables G , M , r , and r^ .

Answer 1

Answer:

   F / m = G M / R²

Explanation:

The equation for the law of universal attraction is

          F = G m M / R²

Where R is the distance to the object from the center of the earth,

       F / m = G M / R²

       

In this case the F / m ratio is called gravity acceleration and is equivalent to the electric field in electricity.

In this case, since the gravitational force is always attractive, the direction of g is towards the center of the body and the quantity R varies very little because the radius of the Earth is very high.

            R = Re + h

           R = Re (1+ h / Re)

Re = 6.37 10⁶ m

We value of h in the Earth is less than 10⁴ m