4m - 9= 31<br><br> I can’t remember how to work this out. Can someone help?

A shipping container is in the shape of a right rectangular prism with a length of 13.5 feet, a width of 4 feet, and a height of

podryga [215]

Answer: 227 pounds.

Step-by-step explanation:

By definition, the volume of a rectangular prism can be calculated with the following formula:

$V=lwh$

Where "w" is the width of the rectangular prism, "l" is the length and "h" is the height of the rectangular prism.

In this case you know that:

$l=13.5\ ft\\\\w=4\ ft\\\\h= 7.5 ft$

Substituting values into the formula, you get that the volume of the shipping container is:

$V=(13.5\ ft)(4\ ft)( 7.5 ft)\\\\V=405\ ft^3$

You know that it was completely filled with contents that weigh 0.56 pound per cubic foot, approximately. Then, its density is:

$d=0.56\ \frac{lb}{ft^3}$

Since:

$d=\frac{m}{V}$

Where "m" is mass and "V" is volume, you can susbstitute values and solve for "m":

$0.56\ \frac{lb}{ft^3}=\frac{m}{405\ ft^3}\\\\(0.56\ \frac{lb}{ft^3})(405\ ft^3)=m\\\\m\approx227\ lb$

8 0

4 years ago

Which number follows the three rules below?

gregori [183]

Answer: 3. 199.751

rounded to nearest tenth is 199.8

rounded to nearest hundredth is 199.75

rounded to nearest whole number is 200.

Hope it helps!

5 0

2 years ago

Read 2 more answers

A restaurant chain wants to change their oil from peanut oil to canola oil in order to save money. However, the restaurant wants

yulyashka [42]

Answer:

yes

Step-by-step explanation:

3 0

3 years ago

A manufacturer considers his production process to be out of control when defects exceed 3%. In a random sample of 100 items, th

pochemuha

Answer:

The p-value of the test is of 0.2776 > 0.01, which means that the we accept the null hypothesis, that is, the manager's claim that this is only a sample fluctuation and production is not really out of control.

Step-by-step explanation:

A manufacturer considers his production process to be out of control when defects exceed 3%.

At the null hypothesis, we test if the production process is in control, that is, the defective proportion is of 3% or less. So

$H_0: p \leq 0.03$

At the alternate hypothesis, we test if the production process is out of control, that is, the defective proportion exceeds 3%. So

$H_1: p > 0.03$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.03 is tested at the null hypothesis

This means that $\mu = 0.03, \sigma = \sqrt{0.03*0.97}$

In a random sample of 100 items, the defect rate is 4%.

This means that $n = 100, X = 0.04$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.04 - 0.03}{\frac{\sqrt{0.03*0.97}}{\sqrt{100}}}$

$z = 0.59$

P-value of the test

The p-value of the test is the probability of finding a sample proportion above 0.04, which is 1 subtracted by the p-value of z = 0.59.

Looking at the z-table, z = 0.59 has a p-value of 0.7224

1 - 0.7224 = 0.2776

The p-value of the test is of 0.2776 > 0.01, which means that the we accept the null hypothesis, that is, the manager's claim that this is only a sample fluctuation and production is not really out of control.

4 0

3 years ago

What is the equation to find area of a parallelogram

olchik [2.2K]

A=BH

Area = Base x the Hight

6 0

3 years ago

4m - 9= 31 I can’t remember how to work this out. Can someone help?