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Natali5045456 [20]
3 years ago
5

or Solve this system of equations by graphing. First graph the equations, and then type the solution. y= 7/4 x–3 y=x

Mathematics
1 answer:
Karolina [17]3 years ago
7 0

Answer:

y =  \frac{7}{4} x - 3 \\ y = x \\ y = \frac{7}{4} y - 3 \\ y - \frac{7}{4} y =  - 3 \\  -  \frac{3}{4} y =  - 3 \\ 3y = 12 \\ y =  \frac{12}{3}  \\ y = 4 = x

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If L=√(x^2+y^2), dx/dt =-4, dy/dt=3, find dL/dt when x=4 and y=3
yulyashka [42]

Hello,

L=\sqrt{x^2+y^2} \\\\\dfrac{dx}{dt}=-4\\\\\dfrac{dy}{dt}=3\\\\x=4, y=3\\\\\dfrac{\partial L} {\partial x} =\dfrac{x}{\sqrt{x^2+y^2}} \\\\\dfrac{\partial L} {\partial y} =\dfrac{y}{\sqrt{x^2+y^2}} \\\\\dfrac{dL}{dt} =\dfrac{\partial L} {\partial x}*\dfrac{dx}{dt}+\dfrac{\partial L} {\partial y}*\dfrac{dy}{dt}\\\\=-4*\frac{-4}{\sqrt{4^2+3^2}} +3*\frac{3}{\sqrt{4^2+3^2}}\\\\=\dfrac{16}{5} +\dfrac{9}{5} \\\\=5\\

5 0
3 years ago
AABC has vertices at A(12, 8), B(4,8), and C(4, 14).
borishaifa [10]

Answer:

<u>Triangle ABC and triangle MNO</u> are congruent. A <u>Rotation</u> is a single rigid transformation that maps the two congruent triangles.

Step-by-step explanation:

ΔABC has vertices at A(12, 8), B(4,8), and C(4, 14).

  • length of AB = √[(12-4)² + (8-8)²] = 8
  • length of AC = √[(12-4)² + (8-14)²] = 10
  • length of CB = √[(4-4)² + (8-14)²] = 6

ΔMNO has vertices at M(4, 16), N(4,8), and O(-2,8).

  • length of MN = √[(4-4)² + (16-8)²] = 8
  • length of MO = √[(4+2)² + (16-8)²] = 10
  • length of NO = √[(4+2)² + (8-8)²] = 6

Therefore:

  • AB ≅ MN
  • AC ≅ MO
  • CB ≅ NO

and ΔABC ≅ ΔMNO by SSS postulate.

In the picture attached, both triangles are shown. It can be seen that counterclockwise rotation of ΔABC around vertex B would map ΔABC into the ΔMNO.

3 0
3 years ago
Helpp!!<br> Simplify : [( 4 1/6 + 2 1/3 ) ÷ 4 1/3 ] - 1 1/2
Nadusha1986 [10]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{0}}}}}

Step-by-step explanation:

\sf{ [ (4 \frac{1}{6}  + 2 \frac{1}{3} )  \div 4 \frac{1}{3}] -  1\frac{1}{2} }

Convert the mixed numbers into improper fraction

\longrightarrow{ \sf{ [ ( \frac{25}{6}  +  \frac{7}{3} ) \div  \frac{13}{3}] -  \frac{3}{2}}}

Add the fractions : 25 / 6 and 7 / 3

While performing addition or subtraction of unlike fractions, you have to express the given fractions into equivalent fractions of common denominator and add or subtract as we do with like fraction.

To do so, first take the L.C.M of 6 and 3 which results to 6

\longrightarrow\sf{ [( \frac{25 + 7 \times 2}{6} ) \div  \frac{13}{3} ] -  \frac{3}{2}}

\longrightarrow{ \sf{ [( \frac{25 + 14}{6} )  \div  \frac{13}{3}  ] -  \frac{3}{2} }}

\longrightarrow{ \sf{ [ \frac{39}{6}  \div  \frac{13}{3}] -  \frac{3}{2} }}

Multiply the dividend by the reciprocal of the divisor.

Reciprocal of any number or fraction can be obtained by interchanging the position of numerator and denominator

\longrightarrow{ \sf{ [  \frac{39}{6}  \times  \frac{3}{13} ] -  \frac{3}{2}}}

To multiply one fraction by another, multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term

\longrightarrow{ \sf{ [  \frac{39 \times 3}{6 \times 13} ] -  \frac{3}{2}}}

\longrightarrow{ \sf{ [  \frac{117}{78}  ] -  \frac{3}{2} }}

\longrightarrow{ \sf{ \frac{3}{2}  -  \frac{3}{2} }}

While performing the addition or subtraction of like fractions , you just have to add or subtract the numerator respectively in which the denominator is retained same

\longrightarrow{ \sf{ \frac{3 - 3}{2} }}

Subtract 3 from 3

\longrightarrow{ \sf{ \frac{0}{2}}}

Divide 0 by 2

\longrightarrow{ \sf{0}}

Hope I helped!

Best regards!

3 0
3 years ago
Gavin works for a skydiving company.
viktelen [127]
What’s the question ? & need additional information
4 0
2 years ago
An unmanned submarine ascends from the ocean floor at a rate of 2 meters per second. If the ocean floor is 4220 feet below sea l
KengaRu [80]

Answer:

a=4220-2t

This would be if we are finding the altitude of the submarine from the surface of the water(how many meters away from the surface it is). I don't know what it would be if you want to know from the bottom of the ocean.

4 0
3 years ago
Read 2 more answers
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