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Alenkinab [10]
3 years ago
6

Assessment: To help assess student learning in her developmental math courses, a mathematics professor at a community college im

plemented pre- and posttests for her students. A knowledge-gained score was obtained by taking the difference of the two test scores.
(a) What type of experimental design is this?
Mathematics
1 answer:
Flauer [41]3 years ago
6 0

Answer: Randomized design.

Step-by-step explanation:

Randomization is the process of assigning the treatments or tested factors to the experimental units in an experiment in accordance to definite laws or probability is technically known as randomization.

A randomized design relies on randomization to control for the effects of extraneous variables.

In a randomized design, objects or subjects are assigned to groups completely at random. One standard method for assigning subjects to treatment groups is labelling each subject and afterwards, using a list of random numbers to select from the labelled subjects. It is used when the experiment has treatment conditions and subjects. Also, subjects are randomly assigned to different treatments.

You might be interested in
Correlation always implies causation. Is this statement correct?
svetoff [14.1K]

Answer:

Correlation does not always imply causation. (It's not correct)

Step-by-step explanation:

Correlation tests 2 variables' relationship, but just because they are related does not mean they necessarily cause each other.

3 0
3 years ago
How does an earthquake of magnitude 7.9 compare in intensity with an earthquake of magnitude of 3.7 on the Richter​ scale? The l
Andre45 [30]
We are required to compare the magnitude for two earthquake intensity:
the larger intensity is 7.9
the smaller intensity is 3.7
thus the ratio of the intensity will be:
(larger intensity)/(smaller intensity)
=7.9/3.7
=2.135
~2 
Thus we conclude that:
The larger earthquake's intensity was 2 times as great as the smaller earthquake's intensity. 

5 0
3 years ago
Can you please help me? Keep it a little basic. (no decimals) Thanks for the help!
Delvig [45]
When you are dividing fractions you just flip the second fraction upside down and multiply the two fractions
So the first is
½ x 6/1 = 6/2 = 3

For the second you write them as improper fractions then do the same
So it is
3/2 / 1/8 = 3/2 x 8/1 = 24/2 = 12

So the answer to the first question is 3 and the second is 12
4 0
3 years ago
Read 2 more answers
Expand the following using the Binomial Theorem and Pascal’s triangle. (x + 2)6 (x − 4)4 (2x + 3)5 (2x − 3y)4 In the expansion o
ivolga24 [154]
\bf (2x+3)^5\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(2x)^5(+3)^0\\
2&+5&(2x)^4(+3)^1\\
3&+10&(2x)^3(+3)^2\\
4&+10&(2x)^2(+3)^3\\
5&+5&(2x)^1(+3)^4\\
6&+1&(2x)^0(+3)^5
\end{array}

as you can see, the terms exponents, for the first term, starts at highest, 5 in this case, then every element it goes down by 1, till it gets to 0

for the second term, starts at 0, and every element it goes up by 1, till it gets to the highest

now, to get the coefficient, they way I get it, is "the product of the current coefficient and the exponent of the first term, divided by the exponent of the second term plus 1"

notice the first coefficient is always 1

so...how did we get 10 for the 3rd element?  well, 5*4/2
how did we get 10 for the fourth element?  well, 10*2/4


\bf (2x-3y)^4\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(2x)^4(-3y)^0\\
2&+4&(2x)^3(-3y)^1\\
3&+6&(2x)^2(-3y)^2\\
4&+4&(2x)^1(-3y)^3\\
5&+1&(2x)^0(-3y)^4
\end{array}


\bf (3a+4b)^8\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(3a)^8(+4b)^0\\
2&+8&(3a)^7(+4b)^1\\
3&+28&(3a)^6(+4b)^2\\
4&+56&(3a)^5(+4b)^3\\
5&+70&(3a)^4(+4b)^4\\
6&+56&(3a)^3(+4b)^5\\
7&+28&(3a)^2(+4b)^6\\
8&+8&(3a)^1(+4b)^7\\
9&+1&(3a)^0(+4b)^8
\end{array}

and from there, you can simplify the elements of the expansion by combining the coefficients

like for example, the 7th element of (3a+4b)⁸ will then be 1032192a²b⁶
7 0
3 years ago
Read 2 more answers
Is this problem convergent or divergent?
Svetllana [295]

Answer:

Its divergent

Step-by-step explanation:

<em><u>HOPE</u></em><em><u> </u></em><em><u>YOU</u></em><em><u> </u></em><em><u>LIKED</u></em><em><u> </u></em><em><u>IT</u></em>

6 0
3 years ago
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