Question

The table below represents the concessions sold at the last three basketball games. Thegames were held on different days and times.Friday nightSaturday morningTuesday nightTotalCandy1489478320Hot Dogs10227150279Nachos1084297247Total358163325846What is the approximately probability of a person going to a Saturday morning game andbuying nachos?

Answer 1

Given:

There are given the table that represents the concessions sold.

Explanation:

According to the question:

We need to find the approximate value of the probability.

So,

We can see that in the question, there is talk about Saturday morning and Nachos.

Then,

The value which is given Saturday morning and buying Nachos is 42.

And,

The total number of values is 846.

So,

From the approximate probability:

$P=\frac{The\text{ value who given in the table of saturday morning and nachos}}{The\text{ total number of value.}}\times100$

So,

$P=\frac{42}{846}\times100$

Then,

$\begin{gathered} P=\frac{42}{846}\times100 \\ P=0.0496\times100 \\ P=4.96\% \\ P=5\% \end{gathered}$

Final answer:

Hence, the correct option is C.