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Rainbow [258]
2 years ago
5

What should she use as her common denominator

Mathematics
1 answer:
Paladinen [302]2 years ago
6 0
3/4+2/3=9/12+8/12
These are some she can use
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Write the value of 83,479
Ann [662]
Eighty three thousand four hundred and seventy nine
6 0
3 years ago
Determine whether the following conjecture is true or false. Give a counterexample if the answer is false.
brilliants [131]
This conjecture is false, A and C don't have to be complementary angles.

Let Angle A be 100 and Angle B be 80 degrees. They are supplementary (sum of 180).
Let Angle C be 100 and Angle B is still 80 degrees. They are supplementary.

However, Angle A and Angle C are not complementary (sum of 90).
4 0
2 years ago
N + 4y + 5n + 3y What is the answer?
Marina86 [1]

Answer: The answer is 6n+7y

Step-by-step explanation: All you have to do is add like terms

5 0
2 years ago
The difference of two numbers is 90 and their quotient is 10
bija089 [108]
To solve this, set up two equations using the information you're given. Let's call our two numbers a and b:
1) D<span>ifference of two numbers is 90
a - b (difference of two numbers) = 90

2) The quotient of these two numbers is 10
a/b (quotient of the two numbers) = 10


Now you can solve for the two numbers.
1) Solve the second equation for one of the variables. Let's solve for a:
a/b = 10
a = 10b

2) Plug a =10b into the first equation and solve for the value of b:
a - b = 90
10b - b = 90
9b = 90
b = 10

3) Using b = 10, plug it back into one of the equations to find the value of a. I'll plug it back into the first equation:
a - b = 90
a - 10 = 90
a = 100

-------

Answer: The numbers are 100 and 10</span>
3 0
3 years ago
What point in the feasible region maximizes the objective function, 3x + y ≤ 12, x+y ≤5, x ≥0,y ≥0
forsale [732]

Step-by-step explanation:

We have to find the point in the feasible region which maximizes the objective function. To find that point first we need to graph the given inequalities to find the feasible region.

Steps to graph 3x + y ≤ 12:

First we graph 3x + y = 12 then shade the graph for ≤.

plug any value of x say x=0 and x=2 into 3x + y = 12 to find points.

plug x=0

3x + y = 12

3(0) + y = 12

0 + y = 12

y = 12

Hence first point is (0,12)

Similarly plugging x=2 will give y=6

Hence second point is (2,6)

Now graph both points and joint them by a straight line.

test for shading.

plug any test point which is not on the graph of line like (0,0) into original inequality 3x + y ≤ 12:

3(0) + (0) ≤ 12

0 + 0 ≤ 12

0 ≤ 12

Which is true so shading will be in the direction of test point (0,0)


We can repeat same procedure to graph other inequalities.

From graph we see that ABCD is feasible region whose corner points will result into maximum or  minimu for objective function.

Since objective function is not given in the question so i will explain the process.

To find the maximum value of objective function we plug each corner point of feasible region into objective function. Whichever point gives maximum value will be the answer

7 0
2 years ago
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