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3 years ago

How to find the minimum value of an expression

Mathematics

2 answers:

AURORKA [14]3 years ago

8 0

Your answer is positive

Tanya [424]3 years ago

7 0

f(x)=9x²+24x+1
f(x)=(3x)²+ 2×3x× 4 + 1
= (3x)²+2×3x×4 +16 -16 +1
=. ( 3x+4)² -15. -------(1)
then (3x+4)² ≥0
least value of (3x+4)² is 0
putting in equation 1
= 0-15 =-15
- 15 is the least value

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the height of a triangle is 7cm greater than its base and its area is 15cm squared. find the value of its height

Rudiy27

Answer:

Step-by-step explanation:

Let base be b, height be h

h = 7+b or we can say that b = h -7

A = 15 cm²

General formula for area of a triangle

A = b · h

Substitute what we know to find the height h

15 = (h-7) · h

15 = h² -7h

0 = h²-7h -15

h = (7 ±√49 + 4·1·15)/2

h = (7 ±√109)/2

h ≈ -1.72 reject this solution because height cannot be negative

h ≈ 8.72 cm

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2 years ago

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Ksju [112]

Answer:

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3 years ago

How to solve this problem

Eddi Din [679]

Answer:

Solving the radical $\pm\sqrt{-81}$ we get $\mathbf{\pm9 \ i}$

Step-by-step explanation:

We need to express the radical $\pm\sqrt{-81}$ using the imaginary unit i

Prime factors of 81 are: 3x3x3x3

and $\sqrt{-1}=i$

Solving:

$\pm\sqrt{-81}\\=\pm\sqrt{81}\sqrt{-1}\\=\pm\sqrt{3\times3\times3\times3}i\\ =\pm\sqrt{3^2\times3^2}i\\=\pm3\times3\ i\\=\pm9 \ i$

So, Solving the radical $\pm\sqrt{-81}$ we get $\mathbf{\pm9 \ i}$

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3 years ago

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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