Answer:
import java.util.ArrayList;
import java.util.Scanner;
import java.util.Collections;
public class num4 {
public static void main(String[] args) {
int sum = 0;
Scanner in = new Scanner(System.in);
System.out.println("Enter number");
int num = in.nextInt();
ArrayList<Integer> list = new ArrayList<>();
while (num >= 0){
list.add(num);
System.out.println("Enter another positive number, enter a negative to stop");
num = in.nextInt();
}
int maximum = Collections.max(list);
int listSize = list.size();
for(int i:list){
sum = sum+i;
}
double average = (double) sum/listSize;
System.out.println("Maximum number entered is "+maximum);
System.out.println("Average of the number is "+average);
}
}
Explanation:
In this program:
- A Scanner class is used to receive user input and store in a variable
- A while loop with the condition while (num >= 0) is used to ensure only non-negative numbers are entered
- An ArrayList is created and used to store all the user's valid entries
- The Max Method in the Collections class is used to find the maximum value entered
- To find the average, a for loop is used to add all elements in the list and divide by the size of the list
- Finally the Average and maximum is printed out
Answer:
Command: Systemoutprintln (b)
Output: 7
Explanation:
To solve this problem, we must take into account the precedence of operation.
The division takes precedence before the addition, so we must divide before we add for b.
So
int b = 4 + 6/2 = 4 + 3 = 7.
So
Command: Systemoutprintln (b)
Output: 7
