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Archy [21]
3 years ago
11

The function below takes one parameter: a string (date_string) containing a date in the mm/dd/year format. Complete the function

to return a list containing integers for each of the date components in month, day, year order. For example, if given the string '06/11/1930', your code should return the list [6, 11, 1930].
Computers and Technology
1 answer:
Natalija [7]3 years ago
8 0

Answer:

The solution code is written in Python 3.

  1. def convertDate(date_string):
  2.    date_list = date_string.split("/")
  3.    for i in range(0, len(date_list)):
  4.        date_list[i] = int(date_list[i])
  5.    return date_list  
  6. print(convertDate('06/11/1930'))

Explanation:

Firstly, create a function convertDate() with one parameter, <em>date_string</em>. (Line 1).

Next, use the Python string <em>split()</em> method to split the date string into a list of date components (month, day & year) and assign it to variable <em>date_list</em>. (Line 3) In this case, we use "/" as the separator.

However, all the separated date components in the <em>date_list</em> are still a string. We can use for-loop to traverse through each of the element within the list and convert each of them to integer using Python<em> int() </em>function. (Line 5 - 6)

At last return the final date_list as the output (Line 8)

We can test our function as in Line 11. We shall see the output is as follow:

[6, 11, 1930]

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rank(A)=rank\left ( \left [ A|B \right ] \right )\:and\:n=rank(A)

rank(A)

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<em>E.g.</em>

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A=\begin{pmatrix}1 & -3 &-2 \\  2& -4 &-3 \\ -3 &6  &8 \end{pmatrix} B=\begin{pmatrix}6\\ 8\\ 5\end{pmatrix}

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