Question

The function below takes one parameter: a string (date_string) containing a date in the mm/dd/year format. Complete the function to return a list containing integers for each of the date components in month, day, year order. For example, if given the string '06/11/1930', your code should return the list [6, 11, 1930].

Answer 1

Answer:

The solution code is written in Python 3.

1. def convertDate(date_string):
3.    date_list = date_string.split("/")
5.    for i in range(0, len(date_list)):
6.        date_list[i] = int(date_list[i])
8.    return date_list  
11. print(convertDate('06/11/1930'))

Explanation:

Firstly, create a function convertDate() with one parameter, date_string. (Line 1).

Next, use the Python string split() method to split the date string into a list of date components (month, day & year) and assign it to variable date_list. (Line 3) In this case, we use "/" as the separator.

However, all the separated date components in the date_list are still a string. We can use for-loop to traverse through each of the element within the list and convert each of them to integer using Python int() function. (Line 5 - 6)

At last return the final date_list as the output (Line 8)

We can test our function as in Line 11. We shall see the output is as follow:

[6, 11, 1930]