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jolli1 [7]
3 years ago
15

What's 9 + 10? Whoever gets it right get's the crown!

Mathematics
2 answers:
nasty-shy [4]3 years ago
4 0

Answer:

Step-by-step explanation:

the answer would be 21

BigorU [14]3 years ago
3 0

Answer:

jokes aside it is 19

Step-by-step explanation:

but if it is jokes then 21

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d=10m

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(π5^2) / 2

=25π/2

=12.5π

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Step-by-step explanation:

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Which point could represent 5/3 ?
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A manufacturer of pharmaceutical products analyzes specimens from each batch of a product to verify the concentration of the act
Alisiya [41]

Answer:

0.82-2.977\frac{0.048}{\sqrt{15}}=0.783    

0.82+2.977\frac{0.048}{\sqrt{15}}=0.857    

So on this case the 99% confidence interval would be given by (0.783;0.857)

So then we can conclude that at 99% of confidence the true mean is between (0.783;0.857) and the specification is satisfied since the value of 0.8 is on the confidence interval

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X= 0.82 represent the sample mean

\mu population mean (variable of interest)

s=0.048 represent the sample standard deviation

n=15 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=15-1=14

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,14)".And we see that t_{\alpha/2}=2.977

Now we have everything in order to replace into formula (1):

0.82-2.977\frac{0.048}{\sqrt{15}}=0.783    

0.82+2.977\frac{0.048}{\sqrt{15}}=0.857    

So on this case the 99% confidence interval would be given by (0.783;0.857)

So then we can conclude that at 99% of confidence the true mean is between (0.783;0.857) and the specification is satisfied since the value of 0.8 is on the confidence interval

5 0
3 years ago
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