Continuing from the setup in the question linked above (and using the same symbols/variables), we have




The next part of the question asks to maximize this result - our target function which we'll call

- subject to

.
We can see that

is quadratic in

, so let's complete the square.

Since

are non-negative, it stands to reason that the total product will be maximized if

vanishes because

is a parabola with its vertex (a maximum) at (5, 25). Setting

, it's clear that the maximum of

will then be attained when

are largest, so the largest flux will be attained at

, which gives a flux of 10,800.
Answer:
4618.14
or 4618
Step-by-step explanation:
From T.S.A = 2
rh + 2

where T.S.A = 1628
1628 = 2
rh + 2

1628 = ( rh +
) 2
by dividing both side by 2
= rh +
259.10 = rh +
rh = 259.10 -
h =
<u> </u>(1)
From Radius + Height = 37
r + h = 37 <u> </u>(2)
by substituting eqn 1 into 2
r +
= 37
by multiplying r to both side
+ 259.10 -
= 37r
259.10 = 37r
r = 
r = 7.00 ≅ 7
From Eqn 2
r + h = 37
7 + h = 37
h = 37 - 7
h = 30
so Volume of a cylinder = 
V =
*
* 30
V = 4618.14
≅ 4618
I would go with 12.5
I’m more of an English person but that’s my best guess.
3/24
1/8
1 divided by 8
=12.5
Hope you get it right :)
Answer:
Step-by-step explanation:
2 calculate rise over run
Answer:
k = 7
Step-by-step explanation:
The given figures are lines f(x) and g(x)
For the line f(x), we have the y-intercept at (0, -3) and slope = (-1 - (-3))/(-3 - 0) = -2/3
Therefore, line f(x) = y - (-3) = -2/3·(x - 0) which gives f(x) = y = -3 - 2·x/3
For the line g(x), the y-intercept is (0, 4), and the slope is (4 - 2)/(0 - 3) = -2/3
The equation of the line g(x) is therefore, g(x) = y - 4 = -2/3·x, which simplifies to the slope and intercept form as g(x) = y = 4 - 2/3·x
Therefore, given that the transformation of f(x) to g(x) is given as g(x) = f(x) + k, we have;
k = g(x) - f(x) = 4 - 2/3·x - (-3 - 2·x/3) = 4 - 2/3·x + 3 + 2·x/3 = 7
∴ k = 7