Because you added 14 cards to your collection, we'll have to subtract that:
40 - 14 = 26
Knowing that 26 cards is half of your old card deck, we know that your old card deck is:
26*2 = 52
You have option b. 52 cards before.
Answer:
6³ = 216
9² = 81
3⁴ = 81
18² = 324
Step-by-step explanation:
6³ = 6 · 6 · 6 = 36 · 6 = 216
9² = 9 · 9 = 81
3⁴ = 3 · 3 · 3 · 3 = 9 · 3 · 3 = 27 · 3 = 81
18² = 18 · 18 = 324
The two number are 39 and 13
<em><u>Solution:</u></em>
Let the two numbers be "a" and "b"
Let the larger number be "a" and the smaller number be "b"
<em><u>Given that, sum of two numbers is 52</u></em>
a + b = 52 ---------- eqn 1
<em><u>One number is 3 times as large as the other number</u></em>
Larger number = 3 times smaller number
a = 3b -------- eqn 2
<em><u>Let us solve eqn 1and eqn 2</u></em>
<em><u>Substitute eqn 2 in eqn 1</u></em>
3b + b = 52
4b = 52
b = 13
<em><u>Substitute b = 13 in eqn 2</u></em>
a = 3(13)
a = 39
Thus the two number are 39 and 13
Jivesh put $50
Stacy put $600
<span>Oliver put $100</span>
Answer:
Each shirt cost $12
Step-by-step explanation:
First, we have to interpret this question and turn each to an equation, letting shirts represent the letter s and ties represent the letter t.
6 shirts and 3 ties cost $79.50 would be interpreted to 6s+3t=79.5 ,and 3 shirts and 2 ties cost $41 would be interpreted to 3s+2t=41
Hence we have two equations, and we solve them simultaneously.
6s+3t=79.5 (Equation 1)
3s+2t=41 (Equation 2)
We can either use the substitution method or the elimination method but for the sake of this question, we use the Elimination method.
6s+3t=79.5 (Equation 1)
3s+2t=41 (Equation 2)
We multiply equation 1 by 2 and we multiply equation 2 by 3, I'm prefer to eliminate the
2(6s+3t=79.5)
12s+6t=159 Equation 3
3(3s+2t=41)
9s+6t=123 Equation 4
We subtract equation 4 from equation 3.
12s+6t=159
9s+6t=123
12s-9s=3s
6t-6t=0
159-123=36
We therefore have
3s=36
Divide both sides by 3
s=36/3
s=12
One shirt cost $12
