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pishuonlain [190]
3 years ago
7

Can someone help me find the x-intercepts of f(x) = 3x^2 + 6x - 24?

Mathematics
1 answer:
gayaneshka [121]3 years ago
5 0
(2,0) and (-4,0) hope this helps❤️
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A six-sided fair die is rolled and a fair coin is tossed. If event M represents getting an odd number on the die and event N rep
Rama09 [41]
Probaility is (desired outcomes)/(total possible outcomes)


odd numbers of dice is 3 (1,3,5)
desired outcomes =3
dice has 6 numbers
total possible outcomes of diece=6
3/6=1/2=dice





coin
tails=1
desired outcomes=1
total possibe=2 since 2 sides (head and tails)
cond poinbabiotiuyy=1/2


they are independend of each other since they do not influence each other
if they were like 'pick 2 collor balls and see what color you get, when you pick one, there is 1 less ball int he bucket so the propbabilit changes'



so
assuming that
P(M and N)= means
'the probability of M and N are both equal to "

The two events are independent. In the given scenario, P(M and N) =1/2.
8 0
3 years ago
3. Which of the following represents the
Vladimir [108]

Answer:

I should help u am busy strongly with mine

7 0
3 years ago
An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.
andrey2020 [161]

Answer:

The probability that A selects the first red ball is 0.5833.

Step-by-step explanation:

Given : An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

To find : What is the probability that A selects the first red ball?

Solution :

A wins if the first red ball is drawn 1st,3rd,5th or 7th.

A red ball drawn first, there are E(1)= ^9C_2 places in which the other 2 red balls can be placed.

A red ball drawn third, there are E(3)= ^7C_2 places in which the other 2 red balls can be placed.

A red ball drawn fifth, there are E(5)= ^5C_2 places in which the other 2 red balls can be placed.

A red ball drawn seventh, there are E(7)= ^3C_2 places in which the other 2 red balls can be placed.

The total number of total event is S= ^{10}C_3

The probability that A selects the first red ball is

P(A \text{wins})=\frac{(^9C_2)+(^7C_2)+(^5C_2)+(^3C_2)}{^{10}C_3}

P(A \text{wins})=\frac{36+21+10+3}{120}

P(A \text{wins})=\frac{70}{120}

P(A \text{wins})=0.5833

6 0
3 years ago
Area of rectangular figures​
iren2701 [21]

Answer:

531 in^2

Step-by-step explanation:

21 x 18 = 378 in^2

17 x 9 = 153 in^2

378 + 153 = 531 in^2

3 0
3 years ago
Which of the following objects show an OBTUSE angle?
antiseptic1488 [7]
And obtuse angle is greater than 90°
6 0
3 years ago
Read 2 more answers
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