1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SashulF [63]
2 years ago
9

Given the triangle below, find the value of x

Mathematics
1 answer:
Nataliya [291]2 years ago
6 0

Answer:

I think it is b I’m not quite sure though. Sorry if wrong…

Step-by-step explanation:

You might be interested in
There are 18 apples on the tree in the Donaldson's front yard.
azamat
13 out of 18 are left
6 0
3 years ago
Read 2 more answers
Select a counter-example that makes the conclusion false. 3is prime, 5 is prime, 7 is prime
Butoxors [25]
5^3+7



Hope i helped.
3 0
3 years ago
Read 2 more answers
Find the value of the following without any exponents.
soldier1979 [14.2K]

Answer:

A.) 1/49

B.) 1/512

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Can someone thoroughly explain this implicit differentiation with a trig function. No matter how many times I try to solve this,
Anton [14]

Answer:

\frac{dy}{dx}=y'=\frac{\sec^2(x-y)(8+x^2)^2+2xy}{(8+x^2)(1+\sec^2(x-y)(8+x^2))}

Step-by-step explanation:

So we have the equation:

\tan(x-y)=\frac{y}{8+x^2}

And we want to find dy/dx.

So, let's take the derivative of both sides:

\frac{d}{dx}[\tan(x-y)]=\frac{d}{dx}[\frac{y}{8+x^2}]

Let's do each side individually.

Left Side:

We have:

\frac{d}{dx}[\tan(x-y)]

We can use the chain rule, where:

(u(v(x))'=u'(v(x))\cdot v'(x)

Let u(x) be tan(x). Then v(x) is (x-y). Remember that d/dx(tan(x)) is sec²(x). So:

=\sec^2(x-y)\cdot (\frac{d}{dx}[x-y])

Differentiate x like normally. Implicitly differentiate for y. This yields:

=\sec^2(x-y)(1-y')

Distribute:

=\sec^2(x-y)-y'\sec^2(x-y)

And that is our left side.

Right Side:

We have:

\frac{d}{dx}[\frac{y}{8+x^2}]

We can use the quotient rule, where:

\frac{d}{dx}[f/g]=\frac{f'g-fg'}{g^2}

f is y. g is (8+x²). So:

=\frac{\frac{d}{dx}[y](8+x^2)-(y)\frac{d}{dx}(8+x^2)}{(8+x^2)^2}

Differentiate:

=\frac{y'(8+x^2)-2xy}{(8+x^2)^2}

And that is our right side.

So, our entire equation is:

\sec^2(x-y)-y'\sec^2(x-y)=\frac{y'(8+x^2)-2xy}{(8+x^2)^2}

To find dy/dx, we have to solve for y'. Let's multiply both sides by the denominator on the right. So:

((8+x^2)^2)\sec^2(x-y)-y'\sec^2(x-y)=\frac{y'(8+x^2)-2xy}{(8+x^2)^2}((8+x^2)^2)

The right side cancels. Let's distribute the left:

\sec^2(x-y)(8+x^2)^2-y'\sec^2(x-y)(8+x^2)^2=y'(8+x^2)-2xy

Now, let's move all the y'-terms to one side. Add our second term from our left equation to the right. So:

\sec^2(x-y)(8+x^2)^2=y'(8+x^2)-2xy+y'\sec^2(x-y)(8+x^2)^2

Move -2xy to the left. So:

\sec^2(x-y)(8+x^2)^2+2xy=y'(8+x^2)+y'\sec^2(x-y)(8+x^2)^2

Factor out a y' from the right:

\sec^2(x-y)(8+x^2)^2+2xy=y'((8+x^2)+\sec^2(x-y)(8+x^2)^2)

Divide. Therefore, dy/dx is:

\frac{dy}{dx}=y'=\frac{\sec^2(x-y)(8+x^2)^2+2xy}{(8+x^2)+\sec^2(x-y)(8+x^2)^2}

We can factor out a (8+x²) from the denominator. So:

\frac{dy}{dx}=y'=\frac{\sec^2(x-y)(8+x^2)^2+2xy}{(8+x^2)(1+\sec^2(x-y)(8+x^2))}

And we're done!

8 0
3 years ago
Can you help me please​
Volgvan
D
Area of a circle is: 兀r✖️r, so 4.1m ➗2 = 2.05, 2.05✖️2.05 = 4.2025
3 0
2 years ago
Other questions:
  • A bag contains 12 red, 30 blue, 20 green, 10 yellow, and 8 black marbles. Nancy chooses 1 marble from the bag. What is the proba
    11·1 answer
  • What's the equation of a line that passes through (-4,-7) and (4,-1)
    13·2 answers
  • Answer asap please??
    13·1 answer
  • What is the scientific notation of 0.0008331
    9·2 answers
  • What’s the answer???????
    7·2 answers
  • Given a system of linear equations: dy/dx = 4x-y dy/dx = x-2y Find the general solution.
    13·1 answer
  • Determine the magnitude of the sum of the two vectors: 2.5i+1.8j; -6i-0.7j
    7·2 answers
  • 1. The coefficient in the term 7xy is (a) 7 (b) 3 (c) 1 (d) 2
    8·1 answer
  • 26) John makes $12 per hour as a lifeguard and $8 per hour at the library.
    8·2 answers
  • Given () = −^3 + 2^2 +(3/2) be the position of a particle moving along the x-axis at time t. At what time will the instantaneous
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!