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2 years ago

Write an equation of the line that passes through (1,-2) and (-5,4)

Mathematics

1 answer:

denis23 [38]2 years ago

7 0

Answer: x+y+1=0

Step-by-step explanation:

m=y2-y1/x2-x1

= 4-(-2) /-5-1

=6/-6

=-1

equation of line

y-y1=m(x-x1)

y-(-2) =-1(x-1)

y+2=-x+1

x-1+y+2=0

x+y+11=0

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Total = $5.33 Tax rate = 8% How much was the item?

kow [346]

Answer:

42.64

Step-by-step explanation:

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3 years ago

Jim writes 10^4 words every day how many words does he writes in 10^3 days?

Alchen [17]

1,000 words

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3 years ago

Days/ cost to rent a truck 1/34 2/50 3/66 4/82 A/ C=16d B/ C= 16d + 18 C/ C= 16d + 16 D/ C=18d + 16

Mamont248 [21]

Use the given information as (x, y) points.
You have
(1, 34)
(2, 50)
(3, 66)
(4, 82)
The difference between renting for 1 day and 2 days is 50 - 34 = 16.
The difference between renting for 2 days and 3 days is 66 - 50 = 16
The difference between renting for 3 days and 4 days is 82 - 66 = 16
For each day you rent you pay $16.
Now look at renting for 1 day.
The rental for 1 day is $16, but for 1 day you pay $34.
$34 - $16 = $18
There is an extra $18 in the rental for every day. The $18 is fixed.
That means, to rent a truck, you must pay a fixed amount of $18 plus $16 per day.

total cost = daily cost + fixed cost
total cost = 16d + 16
c = 16d + 18

3 0

3 years ago

Read 2 more answers

Which of the following is the equation of a line parallel to the line y=-x+1,

stich3 [128]

X+y=5 would be the correct one

7 0

3 years ago

A football team has a probability of .75 of winning when playing any of the other four teams in its conference. If the games are

Alexeev081 [22]

Answer:

0.3164 = 31.64% probability the team wins all its conference games

Step-by-step explanation:

For each conference game, there are only two possible outcomes. Either the team wins it, or they lose. The probability of winning a game is independent of any other game. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A football team has a probability of .75 of winning when playing any of the other four teams in its conference.

The probability means that $p = 0.75$ , and four games means that $n = 4$

If the games are independent, what is the probability the team wins all its conference games?

This is P(X = 4). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{4,4}.(0.75)^{4}.(0.25)^{0} = 0.3164$

0.3164 = 31.64% probability the team wins all its conference games

4 0

3 years ago