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damaskus [11]
2 years ago
9

Write an equation of the line that passes through (1,-2) and (-5,4)

Mathematics
1 answer:
denis23 [38]2 years ago
7 0

Answer: x+y+1=0

Step-by-step explanation:

m=y2-y1/x2-x1

 = 4-(-2) /-5-1

 =6/-6

 =-1

equation of line

y-y1=m(x-x1)

y-(-2) =-1(x-1)

y+2=-x+1

x-1+y+2=0

x+y+11=0

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They represent am unknown number

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Please Help this is Due in 1 hour and I really dont understand any of this. (Question in Image)
bezimeni [28]

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5.14

Step-by-step explanation:

The way i solved this was i found the length of the line by taking the 2 (Width and also "A") and the 7 (The height and also "B"), squared both of them and added them together. Then found the square root. Sense i suck at explaining things this is what the equation should have looked like. \sqrt{(2^{2} +7^{2}) ÷ 2. (Side wait for someone else to answer because i'm 70% sure this is right.

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3 years ago
A lines passes through the points (-4, 7) and (5, -8). What is the slope of the line?
Korvikt [17]

Answer:

C

Step-by-step explanation:

The formula to find the slope of a line is:

(y2 - y1) / (x2 - x1)

We can substitute the points (-4, 7) and (5, -8) to find the slope:

(-8 - 7) / (5 - (-4))

(-15) / (5 + 4)

(-15) / 9

This can be simplified to

- 5 / 3

which is option C

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A cylindrical container that has a capacity of 4000 cubic centimeters is to be produced. The top and bottom of the container are
Aleks04 [339]

Answer:

the optimal size of the cylinder to minimise cost is

radius= R = 7.985 cm ≈ 8 cm

height =h = 19.969 cm ≈ 20 cm

Step-by-step explanation:

Since the cost function is

C= 2*π*R²*c₁+ 2*π*R*h*c₂

where R = cylinder radius , h = height ,c₁= cost of the top material ,c₂ = cost f the side material

The volume of the cylinder is:

V=π*h*R² → h= V/(π* R²)

then

C= 2*π*R²*c₁ + 2*π*R* V/(π* R²) *c₂

C=  2*π*R²*c₁ + 2*π*c₂* V/(π* R) *c₂

the value of h that minimises the cost can be found through dC/dR=0 . Thus

dC/dR=  4*π*R*c₁ - 2*π*c₂* V/(π* R²) = 0

2*R*c₁  - c₂* V/(π* R²) = 0

2*R³*c₁ = c₂* V/π

R = ∛[(c₂/c₁)* (V/(2*π)]

replacing values

R = ∛[(c₂/c₁)* (V/(2*π)] = ∛ [($0.40/$0.50)*4000 cm³/(2*π)] = 7.985 cm

R = 7.985 cm

and the height would be

h= V/(π* R²) = 4000 cm³/[π*(7.985 cm)²]] = 19.969 cm

h= 19.969 cm

6 0
4 years ago
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