Answer:
William will make 12 bags of food and each of the bag will contains 2 cans of fruit and 5 cans of vegetables.
Step-by-step explanation:
Given:
Number of fruits cans = 24
Number of veggies cans = 60
William will have to distribute them in equal bags with equal cans of fruits and vegetables respectively.
For this:
We have to find the GCF (greatest common factor) of 24 and 60.
GCF by listing out the factors method.
Factors of 24 :
Factors of 60 : 
So,
The greatest common factor of
and
is
.
The number of bags William will used for equal distribution = 
Now,
We have to distribute the veggies and fruits in equal number of cans to these
bags.
Number of fruits cans used in each bag =
Number of vegetables can used in each bag = 
We can say that:
William will make 12 bags of food and each of the bag will contains 2 cans of fruit and 5 cans of vegetables.
Step-by-step explanation:
Hey, there!!
Here, one point is A(10,8) and P(8,5) is the midpoint.
Let B(x,y) be the another end point.
Now,
Using midpoint formulae,


Since they are equal,equating with their corresponding elements we get,

or, 16 = 10 + x
or, x=16-10
Therefore, x = 6
Now,

or, 10 = 8 + y
or, y = 2
Therefore, The coordinates of another point are B(6,2)
<em><u>Hope it helps</u></em><em><u> </u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
That is the combination of 10 over 3, which is calculated as the quotient of factorials:
n!/k!(n-k)!
where n = 10 and k = 3:
= 10!/3!(10 - 3)!
= 10!/3!*7!
= (10*9*8)/(3*2*1)
= 720/6
= 120
therefore there a re 120 possible different groups
7/11 = 0.64 because 7+4 = 11 and then divid 7 by the total number