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kotegsom [21]
3 years ago
14

Factor the polynomial 9x-6

Mathematics
2 answers:
Afina-wow [57]3 years ago
6 0

Answer:

3(3x-2)

Step-by-step explanation:

this is factoring 3 out of 9x-6

labwork [276]3 years ago
3 0
The answer would be 3(3x-2).
I hope this helps!
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The greatest common factor (GCF) of 35, 38, and 42 is 1.

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Find the equation of the vertical line through (7,-3)
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X = 7
Is a vertical line that passes through (7,-3).
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elliot drove 202.8 miles and used 6.5 gallons of gasoline.How many miles did he travel per gallon of gasoline?
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Read 2 more answers
Which function is increasing at the highest rate? A. B. A linear function on a coordinate plane passes through (minus 1, 3), and
xenn [34]

The highest rate on increasing is of 12x -6y = -24; Option B is the correct answer.

The options are given in the image attached with the answer

<h3>What is a Function ?</h3>

A function is a law that relates a dependent variable and an independent variable.

It is asked among the options given , which is increasing at the highest rate.

To increase at a rate , the value of the slope , m should be > 0

For the Option 1

for a straight line function , the slope is given by

m = ( y₂ -y₁)/(x₂-x₁)

m = ( -3 -3)/(2- (-1)) = -6 /3 = -2

Therefore the function is decreasing

For Option 2

12x - 6y = -24

-6y = -12x -24

y = 2x +4

m = 2 (increasing)

For option 3

m = (-4 + 5)/(2-1) = 1

For Option 4

(8,0) (0,-4)

m = (-4 -0) /(0-8) = 4/8 = 1/2

The highest rate on increasing is of 12x -6y = -24

Therefore Option B is the correct answer.

To know more about Function

brainly.com/question/21145944

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6 0
2 years ago
Small squares with sides 4 cm were cut from each of the corners of a square piece of cardboard. then it was folded into an open-
DENIUS [597]
Suppose the length of the card board was x cm by x cm
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width=(x-8) cm
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this can be simplified to form a quadratic equation given by:
x²-16x+28=0
solving the quadratic equation we get:
x=2 or x=14
Thus we conclude that the original dimensions was:
length=14 cm ; width=14 cm
7 0
3 years ago
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