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Natasha_Volkova [10]
3 years ago
5

PLEASE HELP PLEASE PLEASE!!!!!!!!

Mathematics
1 answer:
nadya68 [22]3 years ago
7 0

Answer:

SRO and QRO

Step-by-step explanation:

Hope this helps!

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Please help area and perimeter of functions
nalin [4]

Answer:

= 150 square units

Step-by-step explanation:

Area of a right triangle is given by the formula;

1/2 bh ; where b is base and h is the height of the triangle

using Pythagoras  theorem, we can find the height;

h² = 20² - 16²

h = √144

  = 12 units

The base of the small triangle can also be found using Pythagoras theorem;

b² = 15² - 12²

b  = √ 81

   = 9

Therefore;

Area = 1/2 bh

        = 1/2 × 12 × (16+9)

        = 1/2 × 12 × 25

        = 6 × 25

        = 150 square units or 150 u²

     

5 0
4 years ago
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What does the equation 3 + m = 8 mean?
Degger [83]

Answer:

The answer is B

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4 0
3 years ago
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What is 5y+=33u<br> this is not an answer
marishachu [46]

Answer:

y = 33u/5

u = 5y/33

7 0
3 years ago
What is the value of this expression?<br> (11,328)°
lys-0071 [83]

Answer:

6025.532

Step-by-step explanation:

assume the unknown value was Y

11328=188% x Y

multiplying both sides by 100 Divide both sides of the equation by 188 we will arrive at:

Y=3x 100/188

Y=6025.532 %

6 0
3 years ago
What is the distance from the origin (0,0) to the point (34,-78)
pantera1 [17]

Given coordinates (0,0)  and (34,-78).

\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

We \ have\ x_1=0, x_2=34, y_1=0 \ and \ y_2=-78.

\mathrm{The\:distance\:between\:}\left(0,\:0\right)\mathrm{\:and\:}\left(34,\:-78\right)\mathrm{\:is\:}

=\sqrt{\left(34-0\right)^2+\left(-78-0\right)^2}

=2\sqrt{1810}

Distance = 2(42.544) ≈ 85.09.

Therefore, distance from the origin (0,0) to the point (34,-78) is 2\sqrt{1810} \ or 85.09 units.


3 0
3 years ago
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