I think that the sum will always be a rational number
let's prove that
<span>any rational number can be represented as a/b where a and b are integers and b≠0
</span>and an integer is the counting numbers plus their negatives and 0
so like -4,-3,-2,-1,0,1,2,3,4....
<span>so, 2 rational numbers can be represented as
</span>a/b and c/d (where a,b,c,d are all integers and b≠0 and d≠0)
their sum is
a/b+c/d=
ad/bd+bc/bd=
(ad+bc)/bd
1. the numerator and denominator will be integers
2. that the denominator does not equal 0
alright
1.
we started with that they are all integers
ab+bc=?
if we multiply any 2 integers, we get an integer
<span>like 3*4=12 or -3*4=-12 or -3*-4=12, etc.
</span>even 0*4=0, that's an integer
the sum of any 2 integers is an integer
like 4+3=7, 3+(-4)=-1, 3+0=3, etc.
so we have established that the numerator is an integer
now the denominator
that is just a product of 2 integers so it is an integer
<span>2. we originally defined that b≠0 and d≠0 so we're good
</span>therefore, the sum of any 2 rational numbers will always be a rational number <span>is the correct answer.</span>
The formula of the Lateral Area of a cylinder is:
Lateral Area = 2
rh
=2
(12)(60) (altitude is 5×radius)
(5×12=60)
=4523.9 mm² ≈ 4524 m²
Answer is
D. 4524 m²
Answer:
The student is correct.
Step-by-step explanation:
Given that 5x² = 20:
It is true that the value of x = 2 because 2² = 4, and when you multiply 4 with 5, you'll get a product of 20:
5x² = 20
5(2)² = 20
5(4) = 20
20 = 20
Therefore, the student is correct that x = 2.
Answer: same.
Step-by-step explanation:
