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Iteru [2.4K]
3 years ago
14

Which equation is graphed below?A. y=2[x-3]B. y=2[x]-3C. y=[2x-3]D. y2([x]-3)​

Mathematics
1 answer:
kvasek [131]3 years ago
8 0
I think it is C it is probably wrong ☹️
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Please help me with this>If you help me i will give you brainliest
Komok [63]

Answer:

Step-by-step explanation:

So its difficult to show

Y= X-6 so what ever x is, y is six less than that so

X= -4 Y= -10

X= 0 Y=-4

X=4 Y=0

X=8 Y= 4

Then plot these on a graph like co-ordinates (x,y) and draw a straight line through them

Y= 4/3x -2 so whatever x is y is 4/3 and 2 less then that

X=-4 Y= -5

X=0 Y= -2

X=4 Y=1

X= 8 Y= 4

Then plot these on a graph like co-ordinates (x,y) and draw a straight line through them

Y= -2

Find minus 2 on the y axis and draw a horizontal line through it all the way across the grid.

Y= 2+ 1/4x  so whatever x is y is 1/4 of x add 2

X=-8 Y= 0

X= -4  Y = 1

X=0 Y=2

X=4 Y=3

X=8 Y=4

Then plot these on a graph like co-ordinates (x,y) and draw a straight line through them

Do this method for 9

y = 2x -3 so whatever x is, y is  2 times that -3

y=2x +1 so whatever x is y is 2 times that +1

y= 2x so whatever x is y is 2 times that

Then plot the answers on a graph like co-ordinates (x,y) and draw a straight line through them

Make sure to label each line

Hope this helps

4 0
3 years ago
Read 2 more answers
Willing to brainlist solve 16-17 please during this exam
ivann1987 [24]

Answer:

16. B

17. B

Step-by-step explanation:

16. The intercept form of the parabola is

y=a(x-x_1)(x-x_2),

where x_1, x_2 are two x-intercepts.

In your case,

x_1=2\\ \\x_2=-8

so

y=a(x-2)(x-(-8))\\ \\y=a(x-2)(x+8)

To find <em>a</em>, substitute coordinates of the point (-6,-4) parabola is passing through

-4=a(-6-2)(-6+8)\\ \\-4=-16a\\ \\a=\dfrac{1}{4}

and

y=\dfrac{1}{4}(x-2)(x+8)

17. The vertex form of the parabola equation is

-2p(y-k)=(x-h)^2,

where <em>(h,k)</em> are the coordinates of the vertex and sign "-" because parabola goes down.

In your case, vertex is (2,3), so

-2p(y-3)=(x-2)^2

The vertex is 3 units from the focus, then

\dfrac{p}{2}=3\\ \\p=6

The equation of the parabola is

-2\cdot 6(y-3)=(x-2)^2\\ \\y=-\dfrac{1}{12}(x-3)^2+3

8 0
3 years ago
Find the surface area of the pyramid .The surface of the pyramid is _ in2 (Type a whole number .)
garik1379 [7]

Given the figure of a square pyramid

The area pf the base =area of the square of side 14 in =

14\cdot14=196in^2

the area of the sides = 4 times the area of a triangle of a base of 14 in and a height of 12 in

so, the area of the sides =

4\cdot\frac{1}{2}\cdot\text{base}\cdot\text{height}=4\cdot\frac{1}{2}\cdot14\cdot12=336in^2

So, the surface area of the pyramid =

196+336=532in^2

So, the answer will be A = 532 in^2

7 0
1 year ago
What's the outputs of 8 plus10
lukranit [14]
I don't really understand what you're asking, but if you're asking the sum of 8 plus 10, it's 18. Sorry if I didn't help, you can try clarifying though :)
7 0
3 years ago
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Rate my handwriting 1/10​
lukranit [14]

Answer:

8/10

Step-by-step explanation:

thanks for the pts

✌️❤️✌️

7 0
2 years ago
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