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Natali [406]
2 years ago
12

7.

Mathematics
1 answer:
denpristay [2]2 years ago
6 0

Answer:

ABWJRIRISBDBDBHSHS

Step-by-step explanation:

Hatdog HWHWHWHSHSHSQIWIW

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How many hours would someone who earns $7.50 per hour have to work to earn $116.25?
Goshia [24]
Here is your answer:

Need to divide the amount he wants to the amount he gets every hour:

116.25÷7.50=15.5 hours

Which mean he has to work 15 and a half hours

Your answer is...
15.5 or if rounded 16 hours! Hope this Helps!
5 0
3 years ago
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I WILL UPVOTE!!!!! To make 1 1/2 dozen muffins, a recipe uses 1 cup of sugar.
maxonik [38]
Approximately 0.67 of a cup of sugar is needed. Let me know if this isn't right.
3 0
3 years ago
What is the slope of (0,4) and (-4,-3)
prohojiy [21]

Step-by-step explanation:

Given points

( x1 , y1 ) = ( 0, 4)

And

( x2 , y2 ) = ( - 4 , - 3 )

Now

Slope(m)

= ( y2 - y1 ) / ( x2 - x1 )

= ( - 3 - 4) / ( -4 - 0)

= - 7 / - 4

= 7/4

3 0
3 years ago
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What is x if we have angles are 68 and 70
Natasha_Volkova [10]

Answer:

42

Step-by-step explanation:

7 0
3 years ago
Wendy is creating a large soup based on a recipe. Her recipe calls for of a pint of milk, but she only has of a pint of milk, so
xeze [42]

Answer:

She can only make 5/6 of her recipe with the amount of milk that she has.

Step-by-step explanation:

Some data of this problem is missing, the data missing is:

Her recipe calls for 3/4 of a pint of milk and she only has 5/8 of a pint of milk.

Now, to know what's the portion she can do with that amount we need to divide the amount of milk she has by the total amount she needs:

\frac{5}{8} ÷\frac{3}{4}

When we divide we turn the second fraction upside down (the numerator becomes the denominator and viceversa) and multiply, thus:

\frac{5}{8}÷\frac{3}{4}=\frac{5}{8}×\frac{4}{3} =\frac{20}{24}

If we simplify this last expression we have:

\frac{20}{24}=\frac{10}{12}  =\frac{5}{6}

Thus, she can only make 5/6 of her recipe with the amount of milk that she has.

<em>Note: In case the data missing is different, you can apply this same procedure with the fractions you have. </em>

6 0
3 years ago
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