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fenix001 [56]
3 years ago
12

Find the area of the figure below

Mathematics
1 answer:
icang [17]3 years ago
3 0

Answer:

324

Step-by-step explanation:

Simplify it

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<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%28-81%29x%5E%7B2%7D%20%7D" id="TexFormula1" title="\sqrt{(-81)x^{2} }" alt="\sqrt{(
SSSSS [86.1K]

Answer:

We conclude that:

\sqrt{\left(-81\right)x^2}=9ix

Step-by-step explanation:

Given the radical expression

\sqrt{\left(-81\right)x^2}

simplifying the expression

\sqrt{\left(-81\right)x^2}

Remove parentheses:  (-a) = -a

\sqrt{\left(-81\right)x^2}=\sqrt{-81x^2}

Apply radical rule:   \sqrt{-a}=\sqrt{-1}\sqrt{a},\:\quad \mathrm{\:assuming\:}a\ge 0

                 =\sqrt{-1}\sqrt{81x^2}

Apply imaginary number rule:  \sqrt{-1}=i

                 =i\sqrt{81x^2}

Apply radical rule:   \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0

                  =\sqrt{81}i\sqrt{x^2}

                  =9i\sqrt{x^2}

Apply radical rule:  \sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

                  =9ix

Therefore, we conclude that:

\sqrt{\left(-81\right)x^2}=9ix

7 0
3 years ago
Isolated triangle 68 perimeter equal sides more than 10 ft use x for the shorter side formula
Ugo [173]

Answer:

Step-by-step explanation:

Find the perimeter of an isosceles triangle whose equal sides have a size of 10 m each and the angle between them equal to 30°. We need to know all sides in order to find the perimeter of this triangle. Let x be the base of this isosceles triangle.

6 0
2 years ago
True False x-sqrt6 is a factor of x^4-36
Rasek [7]
True because it wouldn’t have made since if it was false
5 0
3 years ago
Is this the right answer?
Ne4ueva [31]
Yes your answer is solved correctly
6 0
3 years ago
Write a quadratic function with zeroes 0 and 8.
Jlenok [28]

Answer:

x^2-8x=0

Step-by-step explanation:

the quadratic function should be as follows:

x^2-8x=0

Now let's confirm that the zeros of the function are 0 and 8

x^2-8x=0=x(x-8)=0

Therefore we can see that if x = 0

0^2*8*0=0\\0=0

the equation is fulfilled

And we also have (x-8)

for this expresion to be equal to zero:

x-8=0\\x=8

thus, if x = 8

8^2-8*8=0\\64-64=0\\0=0

the equation is also fulfilled

The zeros of the quadratic function x^2-8x=0 are 0 and 8.

3 0
3 years ago
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