3 years ago

HELPP?!?!

Mathematics

2 answers:

olganol [36]3 years ago

8 0

What is it that you are needing to calculate?

lapo4ka [179]3 years ago

3 0

Answer: I need more info and I don't know what u need me to do here, I hope u understand.

Step-by-step explanation:

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Last year, Janelle worked as a party planner. She kept track of the number of guests at each of the parties she planned. This bo

Yanka [14]

I think it’s between 100-200 like 150 cause it’s near a 100 and more then a 100 too.

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2 years ago

Suppose that prior to conducting a coin-flipping experiment, we suspect that the coin is fair. How many times would we have to f

BabaBlast [244]

Answer:

153 times

Step-by-step explanation:

We have to flip the coin in order to obtain a 95.8% confidence interval of width of at most .14

Width = 0.14

ME = $\frac{width}{2}$

ME = $\frac{0.14}{2}$

ME = $0.07$

$ME\geq z \times \sqrt{\frac{\widecap{p}(1-\widecap{p})}{n}}$

use p = 0.5

z at 95.8% is 1.727(using calculator)

$0.07 \geq 1.727 \times \sqrt{\frac{0.5(1-0.5)}{n}}$

$\frac{0.07}{1.727}\geq sqrt{\frac{0.5(1-0.5)}{n}}$

$(\frac{0.07}{1.727})^2 \geq \frac{0.5(1-0.5)}{n}$

$n \geq \frac{0.5(1-0.5)}{(\frac{0.07}{1.727})^2}$

$n \geq 152.169$

So, Option B is true

Hence we have to flip 153 times the coin in order to obtain a 95.8% confidence interval of width of at most .14 for the probability of flipping a head

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3 years ago

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bogdanovich [222]

Answer:

I believe the answer is 39.368, if we round that it makes it, 39.4

Step-by-step explanation:

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3 years ago