Surface area of the square pyramid = 217.8 in²
Solution:
Side length of the square = 9 in
Area of the square = side × side
= 9 in × 9 in
= 81 in²
Area of the square = 81 in²
Perimeter of the base = 4 × 9 in = 36 in
Slant height of the triangle = 7.6 in
Surface area of the square pyramid



= 217.8 in²
Surface area of the square pyramid = 217.8 in²
Answer:
two 2
Step-by-step explanation:
First you divide the five over six into the two over three, then you add the quotient of that problem to three over four and the sum is your answer.
if we zero out f(x), namely make y = 0, we can get the roots or x-intercepts for this quadratic equation

now, the equation is in x-terms, meaning is a vertically opening parabola, so the axis of symmetry will be x = something, a vertical line.
well, we have two x-intercepts, one at -4 and another at 2, and the vertex is right half-way between those guys
-4------------(-1)------------2
so the vertex is at x=-1, namely the axis of symmetry is x = -1.
I believe it's not a function because the input (x) 4 has two outputs(y), 2 and 8.
To find this out, just divide 456, by the answer of 4.56
So once you divide that, you get 100.
So, n=100
CHECK:
456 divided by 100=4.56
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Hope this helped :)