ANSWER
Find out the how much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .
To proof
let us assume that the fluid should be drained and replaced with pure antifreeze be x .
As given
A radiator contains 10 quarts of fluid, 30% of which is antifreeze.
Now write 30% in the decimal form

Now write 60% in the decimal form

After drained and replaced the fluid with pure antifreeze than the quantity becomes = ( 10 - x )
The quantity of antifreeze is

The fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .
than the equation becomes

solyving
100x +300 - 30x = 600
70x = 300

x = 4.28 quarts (approx)
Hence 4.28 quarts (approx) fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .
Therefore the option (c.) is correct .
Answer:
R1 - given
R2 - subtraction property of equality
R3 - distribution
S4 - 9x = 61
R5 - division prop. of equality
Step-by-step explanation:
hope this helps :)
Answer:
D
Step-by-step explanation:
Mark as brainllest
Y = mx + b
1) m = slope of the tangent line = derivative at the point (pi/6, 1)
Function: y = 2sinx
Derivative: y ' = 2cosx
evaluate at x = pi/6=> y ' = 2cos(pi/6) = √3
2) equation using the slope and the point (pi/6, 1)
y - 1 = √3 ( x - pi/6 )
y = √3 x - √3(pi/6) +1 =√3 x + 0.093
y = √3 x + 0.093
m = √3, b = 0.093