4 years ago

Are there always the same number of prime numbers between 2 consecutive multiples of 10? Why?

Mathematics

1 answer:

galina1969 [7]4 years ago

4 0

Answer:

Yes it is 5

Step-by-step explanation:

It is 5 because you divide 2 and 10 and it is 5

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Simplify (12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4})(12a 5 −6a−10a 3 )−(10a−2a 5 −14a 4 ) . Write the answer in standard form

Katen [24]

Answer:

$(12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4}) = 14a^{5}+14a^{4}-10a^{3}-16a$

Step-by-step explanation:

Given

$(12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4})$

Required

Simplify

We have:

$(12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4})$

Open brackets

$12a^{5}-6a-10a^{3}-10a+2a^{5}+14a^{4}$

Collect like terms

$12a^{5}+2a^{5}+14a^{4}-10a^{3}-6a-10a$

$14a^{5}+14a^{4}-10a^{3}-16a$

Hence:

$(12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4}) = 14a^{5}+14a^{4}-10a^{3}-16a$

6 0

3 years ago