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AysviL [449]
3 years ago
5

Give the domain and range of the graph.

Mathematics
1 answer:
mafiozo [28]3 years ago
4 0

Answer:

Shown from. explanation below

Step-by-step explanation:

The domain are the values of x = [2,10] and the range are all values of y = [-3,3]

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1.
Komok [63]

Answer:

Future amount (A) = $1,258.77 (Approx)

Step-by-step explanation:

Given:

Amount deposit (p) = $693

Rate of interest monthly (r) = 4.9% / 12 = 0.003833

Number of month (n) = 13 × 12 = 156

Find:

Future amount (A)

Computation:

A = p [1+r]^n \\\\ A = 693 [1+0.003833]^{156}\\\\ A= 693[1.8163]\\\\ A = 1258.77

Future amount (A) = $1,258.77 (Approx)

6 0
3 years ago
can you transform the square shown below into pieces that when put together form five small equal squares whose total area shall
Sunny_sXe [5.5K]

How about this (see attached image):

Use the four cuts as shown in the image (red lines).

Then assemble 5 equal squares by the numbers: 1 center square and the rest are pieced together using two pieces as shown. All five together add up to the same area as original square because we use all pieces.

The way one gets a hint toward a solution is to see how an area of a square of length 1 can be split into 5 equal square areas:

1^2 = 5\cdot x^2\\x = \frac{\sqrt{5}}{5} = \sqrt{\frac{2^2}{5^2}+\frac{1^2}{5^2}}

which indicates we need to find a a triangle with sides 2 and 1 to get the hypotenuse of the right length. That gave rise to the cut pattern (if you look carefully, there are triangles with those side lengths).

6 0
3 years ago
Because of their connection with secant​ lines, tangents, and instantaneous​ rates, limits of the form ModifyingBelow lim With h
Gre4nikov [31]

Answer:

\dfrac{1}{2\sqrt{x}}

Step-by-step explanation:

f(x) = \sqrt{x} = x^{\frac{1}{2}}

f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}

We use binomial expansion for (x+h)^{\frac{1}{2}}

This can be rewritten as

[x(1+\dfrac{h}{x})]^{\frac{1}{2}}

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}

From the expansion

(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots

Setting x=\dfrac{h}{x} and n=\frac{1}{2},

(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots

=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots

Multiplying by x^{\frac{1}{2}},

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots

\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots

The limit of this as h\to 0 is

\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}} (since all the other terms involve h and vanish to 0.)

8 0
3 years ago
For a standard normal distribution find the approximate value of p(z<0.42)
Kruka [31]

Answer:

p(z<0.42) = 0.6628

Step-by-step explanation:

A normal distribution with a mean of 0 and a standard deviation of 1 is called a standard normal distribution. That is to say:

μ = 0

σ² = 1

Using a calculator, we find that:

p(z<0.42) = 0.6628 (See picture attached)

8 0
4 years ago
Read 2 more answers
PLEASE help me! The question is attached.
ycow [4]

Answer:

The third option is correct

Step-by-step explanation:

We can rule out the first option because systems of equations CAN have decimal answers (this certain question cannot because of the domain) Same for the second option.

The last option says that all the numbers of forks knives and spoons must be equal but the question never specified that, in fact it looks like that is impossible since the variables have different coefficients.

The only logical answer is number 3

4 0
3 years ago
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