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user100 [1]
3 years ago
11

In two or more complete sentences, identify the parent function, and describe the transformations that were applied to

Mathematics
1 answer:
pantera1 [17]3 years ago
3 0

Answer:

Step-by-step explanation:

Transformed of the function has been given as,

f(x) = \sqrt{(2x+6)}+3

     = \sqrt{2}(\sqrt{x+3})+3

Parent function of this transformed function = \sqrt{x}

Vertical stretch = By a factor of \sqrt{2}

Horizontal shift = 3 units to the left

Vertical shift = 3 units up

Now we can summarize these transformations as,

1). Parent function g(x) = \sqrt{x} has been vertically stretched by a factor of \sqrt{2}

2). Followed by the translations of 3 units left and 3 units up.

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Given m||n, find the value of x
Salsk061 [2.6K]

Answer:

x = 155º

Step-by-step explanation:

y = 25°    {Vertically opposite angles}

x + y = 180    {Co-interior angles are supplementary}

x + 25 = 180

Subtract 25 from both sides

x = 180 - 25

x = 155°

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3 years ago
Can someone help me figure this one please
Norma-Jean [14]

Answer:

9.25

Step-by-step explanation:

5 x .3 = 1.5

20 - 1.5 = 18.5

18.5/2 = 9.25

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3 years ago
a maxicool consists of a cone full of ice cream with a hemisphere of ice cream on top. the radius of a hemisphere is 3cm. The he
Gemiola [76]

According to the information, it can be inferred that the volume of the ice cream is close to 207.33 cm³

<h3>How to calculate the volume of the maxicool?</h3>

To calculate the volume of the maxicool, we must calculate the volume of the sphere of ice cream, and the volume of the cone that is filled with ice cream.

<h3>Volumen of the sphere</h3>

V = \frac{4}{3} × π × R³

V = \frac{4}{3} × π × 3³

V = 113.09 cm³

<h3>Cone volume</h3>

V = \frac{1}{3} × π × R² × <em>h</em>

V = \frac{1}{3} × π × 3² × 10

V= 94.24 cm³

Finally we must add both values to know the total volume of the maxicool.

113.09 + 94.24 = 207.33 cm³

Learn more about volume in: brainly.com/question/13338592

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3 years ago
F(x)= <br> 4<br><br> x<br> ​ <br> +6, find f^{-1}(x)f <br> −1<br> (x).
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3 years ago
A water tank is in the shape of a right circular cone as shown above. The diameter of the cone is 10 feet, and the height is 15
Vsevolod [243]

Answer:

The rate at which the height of the water tank is changing is approximately 0.4244 ft/hour

Step-by-step explanation:

The given parameters are;

The diameter of the cone = 10 feet

The height of the cone = 15 feet

The rate at which water is leaking from the tank, (dV/dt) = 12 ft³/h

The volume of water in the tank = 27·π cubic feet

The volume V of a right circular cone with radius r and height h = 1/3×π×r²×h

The rate of change of the volume, dV, with time dt is given as follows;

The radius of the cone when the volume of the water in the tank is 27·π cubic feet is given as follows;

1/3×π×r²×h = 27·π ft³

The ratio of the height to the radius of the cone is h/r = 15/5 = 3

h/r = 3

∴ r =h/3

The volume of the cone, V = 1/3×π×r²×h = 1/3×π×(h/3)²×h = 1/27×π×h³ =  h³/27×π

dV/dt = dV/dh × dh/dt

Which gives;

12 = d(h³/27×π)/dh × dh/dt = π×h²/9 × dh/dt

dh/dt = 12/(π×h²/9)

At 27·π ft³ = 1/27×π×h³ ft³, we have;

27 = 1/27×h³

27² = h³

h = ∛27² = 9

∴ dh/dt = 12/(π×h²/9) = 12/(π×9²/9) = 12/(π×9) = 4/(3·π) ≈ 0.4244 ft/hour

The rate at which the height of the water tank is changing ≈ 0.4244 ft/hour.

6 0
3 years ago
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