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2 years ago

Given (x – 7)2 = 36, select the values of x.

Mathematics

2 answers:

yanalaym [24]2 years ago

8 0

X 42 is the answer dude

aksik [14]2 years ago

4 0

Answer:

x=1,13

Step-by-step explanation:

(x – 7)^2 = 36

Take the square root of each side

sqrt((x – 7)^2) = sqrt(36)

x-7 = ±6

x-7 = 6 x-7 =-6

Add 7 to all sides

x-7+7 = 6+7 x-7+7 = -6+7

x = 13 x=1

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How do you simplify(n!)^2/(n+1)!(n-1)!

ANTONII [103]

We haven n! = (n-1)! x n and (n+1)! = n! x (n + 1);
Then, (n!)^2 = n! x n! = n! x (n-1)! x n;
And (n+1)!(n-1)! = n! x (n + 1) x (n-1)!;
Finally, [n! x (n-1)! x n] / [n! x (n + 1) x (n-1)!] = (n+1)/n;

5 0

2 years ago

Roselyn is a college student with two part-time jobs. She works a few hours a day at the college laboratory, which pays her at a

VladimirAG [237]

Answer:

15 hours.

Step-by-step explanation:

We first need to see how much money Rose would earn if she sold the 10 pendents, so we will multiply 4×10.

4×10=40

Now we know, she already has 40 dollars of the 160 dollars she needs.

To find out how much she needs left, we will subtract 40 from 160.

160-40=120

She needs a total of 120 more dollars from working.

To find out how many hours she needs to work, we will divide 120 by 8.

120÷8=15.

In conclusion, she needs to work for at least15 hours to receive enough money.Please help me by marking this brainliest, and giving a thanks!

8 0

2 years ago

(A) A small business ships homemade candies to anywhere in the world. Suppose a random sample of 16 orders is selected and each

Leviafan [203]

Following are the solution parts for the given question:

For question A:

$\to (n) = 16$

$\to (\bar{X}) = 410$

$\to (\sigma) = 40$

In the given question, we calculate $90\%$ of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

$\to \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{S}{\sqrt{n}}$

$\to C.I= 0.90\\\\\to (\alpha) = 1 - 0.90 = 0.10\\\\ \to \frac{\alpha}{2} = \frac{0.10}{2} = 0.05\\\\ \to (df) = n-1 = 16-1 = 15\\\\$

Using the t table we calculate $t_{ \frac{\alpha}{2}} = 1.753$ When $90\%$ of the confidence interval:

$\to 410 \pm 1.753 \times \frac{40}{\sqrt{16}}\\\\ \to 410 \pm 17.53\\\\ \to392.47 < \mu < 427.53$

So $90\%$ confidence interval for the mean weight of shipped homemade candies is between $392.47\ \ and\ \ 427.53$ .

For question B:

$\to (n) = 500$

$\to (X) = 155$

$\to (p') = \frac{X}{n} = \frac{155}{500} = 0.31$

Here we need to calculate $90\%$ confidence interval for the true proportion of all college students who own a car which can be calculated as

$\to p' \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{p'(1-p')}{n}}$

$\to C.I= 0.90$

$\to (\alpha) = 0.10$

$\to \frac{\alpha}{2} = 0.05$

Using the Z-table we found $Z_{\frac{\alpha}{2}} = 1.645$

therefore $90\%$ the confidence interval for the genuine proportion of college students who possess a car is

$\to 0.31 \pm 1.645\times \sqrt{\frac{0.31\times (1-0.31)}{500}}\\\\ \to 0.31 \pm 0.034\\\\ \to 0.276 < p < 0.344$

So $90\%$ the confidence interval for the genuine proportion of college students who possess a car is between $0.28 \ and\ 0.34.$

For question C:

In question A, We are $90\%$ certain that the weight of supplied homemade candies is between 392.47 grams and 427.53 grams.
In question B, We are $90\%$ positive that the true percentage of college students who possess a car is between 0.28 and 0.34.

Learn more about confidence intervals:

brainly.in/question/16329412

7 0

2 years ago

Please help me with this one question. THANKS!

geniusboy [140]

The answer is A y-28=3(x-6)

4 0

2 years ago

Help me ASAP!!!!!!!!!!!!!:)

kenny6666 [7]

Answer:

I think it is wrong because it is unlike term

5 0

3 years ago

Read 2 more answers